Answer:
option 4.
16 square units
Step-by-step explanation:
as we do not have the measures of the sides, but if the points of the vertices with Pythagoras we can calculate the sides.
P = (2 , 4)
S = (4 , 2)
we have to subtract the values of p from s
PS = (4 - 2 , 2 - 4)
PS = (2 , -2)
by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2
h: hypotenuse
c1: leg 1
c2: leg 2
PS^2 = 2^2 + -2^2
PS = √ 4 + 4
PS = √8
PS = 2√2
S = (4 , 2)
R = (8 , 6)
SR = (8-4 , 6-2)
SR = (4 , 4)
by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2
h: hypotenuse
c1: leg 1
c2: leg 2
SR^2 = 4^2 + 4^2
SR = √ (16 + 16)
SR = √32
SR = 4√2
having the values of 2 of its sides we multiply them and obtain their area
PS * RS = Area
2√2 * 4√2 =
16
Answer:
0 2
1 4 ⟌ 3 7
- 0
3 7
- 2 8
9
2 r 9
for 37 divided by 14
0 7
1 3 ⟌ 9 6
- 0
9 6
- 9 1
5
7 r 5
for 96 divided by 13
0 2 0
4 1 ⟌ 8 5 8
- 0
8 5
- 8 2
3 8
- 0
3 8
for 858 divided by 41
20 r 38
Step-by-step explanation:
1.2 is the answer to your question.
B
but i have to write more to let me post this so here it is
Answer:
f(x)=349525
Step-by-step explanation:
f(x)=2(3x-4)^2+5
f(x)= 6x - 8^7
f(x)= 6x - 2,097,152
f(-6x)= - 2,097,152
/-6x /-6x
f(x)=349525
I hope I am not terribly wrong but I probably am good luck
