Answer: (A) ![A=300l-l^{2}](https://tex.z-dn.net/?f=A%3D300l-l%5E%7B2%7D)
(B) Length varies between 1 and 150
(C) Largest area is 22500ft²
Step-by-step explanation: Suppose length is l and width is w.
The rectangular garden has perimeter of 600ft, which is mathematically represented as
![2l+2w=600](https://tex.z-dn.net/?f=2l%2B2w%3D600)
Area of a rectangle is calculated as
![A=lw](https://tex.z-dn.net/?f=A%3Dlw)
Now, we have a system of equations:
![2l+2w=600](https://tex.z-dn.net/?f=2l%2B2w%3D600)
![A=lw](https://tex.z-dn.net/?f=A%3Dlw)
Isolate w, so we have l:
![2w=600-2l](https://tex.z-dn.net/?f=2w%3D600-2l)
w = 300 - l
Substitute in the area equation:
A = l(300 - l)
A = 300l - l²
(A) <u>Function of area in terms of length is given by </u><u>A = 300l - l²</u>
(B) The practical domain for this function is values between 1 and 150.
(C) For the largest area, we need to determine the largest garden possible. For that, we take first derivative of the function:
A' = 300 - 2l
Find the values of l when A'=0:
300 - 2l = 0
2l = 300
l = 150
Replace l in the equation:
w = 300 - 150
w = 150
Now, calculate the largest area:
A = 150*150
A = 22500
<u>The largest area the fence can enclose is </u><u>22500ft².</u>