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Mekhanik [1.2K]
3 years ago
5

Find the Coordinates for Point E.

Mathematics
1 answer:
slava [35]3 years ago
7 0

Answer:

The coordinates for point E are (0, 1.5)

Hope this helps!!

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(x+5)(x-4)(x+2) is identical to x^3+ax^2
nikdorinn [45]

Answer:

a = 3

Step-by-step explanation:

Factorize (x+5)(x-4)(x+2)

(x+5)(x-4)(x+2)

=  (x²-4x+5x-20)(x+2)

= (x²+x-20)(x+2)

= (x³+2x²+x²+2x-20x-40)

= x³+3x²-18x -40

Compare with x^3+ax^2

3x² = ax²

3 = a

Rearrange

a = 3

Hence the value of a that makes the expressions identical is 3

4 0
3 years ago
What's the answer to my problem with steps
galben [10]
The radius is half of the diameter, and half of 9 is 4.5. That is your answer. Hope this helps! Have a nice night.
4 0
4 years ago
Read 2 more answers
Suppose \nabla f (x,y) = 3 y \sin(xy) \vec{i} + 3 x \sin(xy)\vec{j}, \vec{f} = \nabla f(x,y), and c is the segment of the parabo
Anna11 [10]

I'll assume you're supposed to compute the line integral of \nabla f over the given path C. By the fundamental theorem of calculus,

\displaystyle\int_C\nabla f(x,y)\cdot\mathrm d\vec r=f(4,48)-f(1,3)

so evaluating the integral is as simple as evaluting f at the endpoints of C. But first we need to determine f given its gradient.

We have

\dfrac{\partial f}{\partial x}=3y\sin(xy)\implies f(x,y)=-3\cos(xy)+g(y)

Differentiating with respect to y gives

\dfrac{\partial f}{\partial y}=3x\sin(xy)=3x\sin(xy)+\dfrac{\mathrm dg}{\mathrm dy}\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C

and we end up with

f(x,y)=-3\cos(xy)+C

for some constant C. Then the value of the line integral is -3\cos192+3\cos3.

8 0
4 years ago
Help please! 16 points
emmainna [20.7K]

Answer:

3

Step-by-step explanation:

divide the top number by the bottom to always find the constant of proportionality :D

6 0
3 years ago
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What interest will be charged on a $300 loan for 6 months if the rate is 18% simple interest?
Yakvenalex [24]

Answer: 540.00

Step-by-step explanation:

4 0
3 years ago
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