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Mashutka [201]
3 years ago
12

In a six-sided dice game, a prize is won if the arithmetic mean of number rolled is 3.25-3.75. In a second game, a prize is won

if the arithmetic mean is more than 4.5. In which game would you rather roll the dice 20 times or 200 times?
Mathematics
2 answers:
gavmur [86]3 years ago
6 0

Answer:

200 times for the first game, and 20 times for the second game

Step-by-step explanation:


emmasim [6.3K]3 years ago
4 0
Answer: In both options, you should play game number 1 with a winning mean score of 3.25 to 3.75.

To find the average when you roll a die, you need to about up all the values in the set and divide by the number of data points.

In this case, 1 + 2 + 3 + 4 + 5 + 6 = 21 / 6 = 3.5

Since the mean is 3.5, that is what you are most likely to average for your score. Regardless of the number of rolls, this is most likely. Therefore, select the first game.
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How to do this and find the max or min points
Veronika [31]
I see your last line is : c(x) = 0.9(x^2-10)^2 + 101.1

Let y = x^2, then c(y) = 0.9(y-10)^2 + 101.1

Apparently, c(y) is a parabola, min is 101.1 when y = 10, max is infinity

So let x^2 = 10 -> x = sqrt(10) or -sqrt(10), min is 101.1, max is infinity
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What percent of 200 is .5?
sergiy2304 [10]
Is it 0.5? if so, the answer is 0.25%
if it is supposed to be just a 5 then the answer would be 2.5%
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3 years ago
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amm1812
The final answer that i got from this was -x-13

6 0
2 years ago
I write out all the whole numbers, starting from 1. If I wrote 1994 digits altogether, what was the last complete number I wrote
Nataly_w [17]

Answer:

You wrote the numbers from 1 to 9: 9 digits.

You wrote the numbers from 10 to 99: 90*2 = 180 digits.

You have written 189 digits.

Then you wrote another 1994 - 189 = 1805

All the numbers from 100 to 999 have 3 digits

So you wrote 1805/3 = 601 2/3

This means 601 full numbers and 2 digits from the 602. number.

So 100 + 601 - 1 = 700 was the last number you wrote.

Do you agree?


3 0
3 years ago
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