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Mashutka [201]
3 years ago
12

In a six-sided dice game, a prize is won if the arithmetic mean of number rolled is 3.25-3.75. In a second game, a prize is won

if the arithmetic mean is more than 4.5. In which game would you rather roll the dice 20 times or 200 times?
Mathematics
2 answers:
gavmur [86]3 years ago
6 0

Answer:

200 times for the first game, and 20 times for the second game

Step-by-step explanation:


emmasim [6.3K]3 years ago
4 0
Answer: In both options, you should play game number 1 with a winning mean score of 3.25 to 3.75.

To find the average when you roll a die, you need to about up all the values in the set and divide by the number of data points.

In this case, 1 + 2 + 3 + 4 + 5 + 6 = 21 / 6 = 3.5

Since the mean is 3.5, that is what you are most likely to average for your score. Regardless of the number of rolls, this is most likely. Therefore, select the first game.
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Manuel bought a shirt and a sweater for a total price of $65. The price of the sweater was $5 more than twice the price of the s
Annette [7]

Answer:

$20

Step-by-step explanation:

Since we are talking about the unknown cost of a shirt AND a sweater, we are dealing with 2 unknowns.  However, we can only have one unknown in a single equation or we cannot solve it.  The cost of the sweater is based on the cost of the shirt, so the shirt will be our "main" unknown.

Cost of the shirt:  x

Since the sweater is $5 more than (this is addition) twice (that is 2 times) the cost of the shirt, the expression for the sweater is 2x + 5

The cost of both is (equals) 65.

x + 2x + 5 = 65 and

3x + 5 = 65 and

3x = 60 so

x = 20

The shirt cost $20 so the sweater had to cost 65 - 20 = 45

3 0
3 years ago
MR MARK MARKS HIS CLASS ON A NORMAL CURVE. THOSE WITH z-SCORES ABOVE 1.8 WILL RECEIVE AN A, THOSE
lukranit [14]

Using the normal distribution, it is found that the percentages are given as follows:

  • 3.59% of the grades will be A.
  • 9.98% of the grades will be B.
  • 74.92% of the grades will be C.
  • 8.64% of the grades will be D.
  • 2.87% of the grades will be F.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The prorportion of students who receive an A is <u>one subtracted by the p-value of Z = 1.8</u>.

Looking at the z-table, Z = 1.8 has a p-value of 0.9641.

1 - 0.9641 = 0.0359.

3.59% of the grades will be A.

For B, it is the <u>p-value of Z = 1.8 subtracted by the p-value of Z = 1.1</u>, hence:

0.9641 - 0.8643 = 0.0998.

9.98% of the grades will be B.

For C, it is the <u>p-value of Z = 1.1 subtracted by the p-value of Z = -1.2</u>, hence:

0.8643 - 0.1151 = 0.7492.

74.92% of the grades will be C.

For D, it is the <u>p-value of Z = -1.2 subtracted by the p-value of Z = -1.9</u>, hence:

0.1151 - 0.0287 = 0.0864.

8.64% of the grades will be D.

For F, it is the <u>p-value of Z = -1.9</u>, hence 2.87% of the grades will be F.

More can be learned about the normal distribution at brainly.com/question/15181104

#SPJ1

7 0
1 year ago
The sales price of an LCD TV is $280, representing 30% off the regular price. What is the original price?
musickatia [10]

Answer:

$400

Step-by-step explanation:

Let 'p' represent the original price, the 'p-0.3p' represents the sale price:

280 = p - 0.3p .

Solving for 'p' we have p=400.

The original price of the television was $400

4 0
3 years ago
Write as an equation: Sara spent $2 more than Lauren, and together they spent $19.
kupik [55]

Answer:

Equations:

a + b = 19

a = b + 2

a = Money that spent Laura

b = Money that spent Laureen

then:

(b+2) + b = 19

2b + 2 = 19

2b = 19-2

2b = 17

b = 17/2

b = 8.5

a = b + 2

a = 8.5 + 2

a = 10.5

Check:

10.5 + 8.5 = 19

5 0
3 years ago
URGENT HELP PLEASE.
AlladinOne [14]
W + 2w = 60

this equation is wrong
6 0
3 years ago
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