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3 years ago

What is the degree of each polynomial?

Mathematics

1 answer:

GREYUIT [131]3 years ago

3 0

Answer:

A- 4

B- 5

C- 8

D- 4

E- 2

F- 7

I'm 99% sure these are right!! I hope this helps :(

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What’s the solution set for x? Can someone please answer and explain how they got they’re answer for 40 points.

xz_007 [3.2K]

Answer:

i think the answer is 2.I had a problem like this and i think u have to find out what both of them equal

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2 years ago

Determine the domain of the function (fog)(x) where f(x)=3x-1/x-4 and g(x)=x+1/x

Katarina [22]

Answer: (-∞,-1) ∪ (0,+∞)

Step-by-step explanation: The representation fog(x) is a representation of composite function, meaning one depends on the other.

In this case, fog(x) means:

fog(x) = f(g(x))

fog(x) = $3(x+\frac{1}{x} )-\frac{1}{x+\frac{1}{x} } -4$

$fog(x)=3x+\frac{3}{x} -\frac{1}{\frac{x^{2}+x}{x} } -4$

$fog(x)=3x+\frac{3}{x} -\frac{x}{x^{2}+x} -4$

$fog(x)=\frac{3x^{2}(x^{2}+x)+3(x^{2}+x)-x-4x(x^{2}+x)}{x(x^{2}+x)}$

$fog(x)=\frac{3x^{4}+3x^{3}+3x^{2}+3x-x-4x^{3}+4x^{2}}{x(x^{2}+x)}$

$fog(x)=\frac{3x^{4}-x^{3}-x^{2}+2x}{x(x^{2}+x)}$

This is the function fog(x).

The domain of a function is all the values the independent variable can assume.

For fog(x), denominator can be zero, so:

$x(x^{2}+x) \neq 0$

If x = 0, the function doesn't exist.

$x^{2}+x \neq0$

$x(x+1) \neq0$

$x+1\neq0$

$x\neq-1$

<u>Therefore, the domain of this function is: </u><u>-∞ < -1 or x > 0</u>

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3 years ago

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Step-by-step explanation:

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2 years ago

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hjlf

Answer:Yes, it is

Step-by-step explanation:

2^2+4(2)-12=0

4+8-12=0

12-12=0

0=0

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3 years ago

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He can now breath fire

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