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3 years ago

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Domain Range -3 6 5 3 -2. 1

1 answer:

uranmaximum [27]3 years ago

3 0

Hello there!

Domain={-3,5,2}
Range={6,3,1}

Hope this helps

Have a great day/night

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If you can tell me what the missing number is.

Orlov [11]

Answer:

6

Step-by-step explanation:

So, to start answering this, lets recall the formula for a rectangles volume:

This formula is :

V=h*w*l

Lets plug in what we know, and solve for the missing variable.

We know that height(h) is 7.

We know that width(w) is 9.

We know that volume(V) is 378.

We are missing length(l)

So:

378=7*9*l

To find length(l), we must iscolate it.

To do this, we must get rid of the 7 and 9.

So lets start by dividing 378 by 9:

378/9=7*9/9*l

=

42=7*l

Now lets do the same thing with the 7 to iscolate l:

42/7=7/7*l

=

6=l

So our missing length(l) is 6.

Answer:

l = 6

Hope this helps!

5 0

3 years ago

X/3 equals 1351 over seven

Fantom [35]

X/3=1351/7
cross multiply
7x=4053
divide by seven on both sides
x=579

5 0

3 years ago

Show √7 , √5 on a number line. <br><br>please hurry up my cissy and oppa<br>

tankabanditka [31]

Answer:

Draw the number line like in the picture.

Step-by-step explanation:

√5 is about 2.236, meaning it's kind of close to 2.25.

√7 is about 2.646, meaning it's very close to 2.625.

5 0

3 years ago

Which model can be used to represent 0.111

weeeeeb [17]

Answer:

11.8845

Step-by-step explanation:

11.8845 to the up and down answer it will be down

4 0

3 years ago

Please help! i dont understand

kvv77 [185]

QUESTION 1

The given inequality is

$y\leq x-3$ and $y\geq -x-2$ .

If (3,-2) is a solution; then it must satisfy both inequalities.

We put x=3 and y=-2 in to both inequalities.

$-2\leq 3-3$ and $-2\geq -3-2$ .

$-2\leq 0$ :True and $-2\geq -5$ :True

Both inequalities are satisfied, hence (3,-2) is a solution to the given system of inequality.

QUESTION 2

The given inequality is

$y\:>\:-3x+3$ and $y\:>\: x+2$ .

If (1,4) is a solution; then it must satisfy both inequalities.

We put x=1 and y=4 in to both inequalities.

$4\:>\:-3(1)+3$ and $4\:>\: 1+2$ .

$4\:>\:0$ :True and $4\:>\: 3$ :True

Both inequalities are satisfied, hence (1,4) is a solution to the given system of inequality.

Ans: True

QUESTION 3

The given inequality is

$y\leq 3x-6$ and $y\:>\: -4x+2$ .

If (0,-2) is a solution; then it must satisfy both inequalities.

We put x=0 and y=-2 in to both inequalities.

$-2\leq 3(0)-6$ and $-2\:>\: -4(0)+2$ .

$-2\leq -6$ :False and $-2\:>\:2$ :False

Both inequalities are not satisfied, hence (0,-2) is a solution to the given system of inequality.

Ans:False

QUESTION 4

The given inequality is

$2x-y\:$ and $x+y\:>\:-1$ .

If (0,3) is a solution; then it must satisfy both inequalities.

We put x=0 and y=3 in to both inequalities.

$2(0)-3\:$ and $0+3\:>\:-1$ .

$-3\:$ :True and $3\:>\:-1$ : True

Both inequalities are satisfied, hence (0,3) is a solution to the given system of inequality.

Ans:True

QUESTION 5

The given system of inequality is

$y\:>\:2x-3$ and $y\:$ .

If (-3,0) is a solution; then it must satisfy both inequalities.

We put x=-3 and y=0 in to both inequalities.

$0\:>\:2(-3)-3$ and $0\:$ .

$0\:>\:-9$ ;True and $0\:$ :True

Both inequalities are satisfied, hence (-3,0) is a solution to the given system of inequality.

Ans:True

3 0

3 years ago