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3 years ago

Domain Range -3 6 5 3 -2. 1

Mathematics

1 answer:

uranmaximum [27]3 years ago

3 0

Hello there!

Domain={-3,5,2}
Range={6,3,1}

Hope this helps

Have a great day/night

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A number is decreased by 40% to 525. what is the original amount?

zhenek [66]

Answer:

875

Step-by-step explanation:

lets assume the original amount X

the new amount = X - ( X × 40% )

525 = (60 × X) ÷ 100

X = ( 525 × 100 ) ÷ 60

X = 875

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2 years ago

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Which of the following number sentences is true? A -9=9 B-9=-(9) C 9=(-9) D 9=-(-9)

kondaur [170]

Answer:

A and D are the true number sentences

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3 years ago

In another survey, Jane found that 25% of the total number of teenagers surveyed like sandwiches. If 50 teenagers like sandwiche

34kurt

Set up a proportion: 25/100 = 50/n where n = # of teens surveyed
Simplify fraction: 1/4 = 50/n
Cross multiply: n = 200
So 200 teens were surveyed.

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3 years ago

Between the time Iko woke up and lunchtime,the temperature rose by 11°.Then by the time he went to bed,the temperature dropped b

natali 33 [55]

Answer: Cannot be done

Step-by-step explanation:

This is impossible as there is no previous information and we don’t have a formula.

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3 years ago

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A survey of 542 consumers reveals that 301 favor the new design for a product. Construct a 90% confidence interval for the true

kodGreya [7K]

Answer:

The 90% confidence interval for the true proportion of all consumers who favor the design is (0.52, 0.59).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 542, \pi = \frac{301}{542} = 0.555$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.555 - 1.645\sqrt{\frac{0.555*0.445}{542}} = 0.52$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.555 + 1.645\sqrt{\frac{0.555*0.445}{542}} = 0.59$

The 90% confidence interval for the true proportion of all consumers who favor the design is (0.52, 0.59).

5 0

3 years ago