Answer:
probability of a crash with at least one fatality if a driver drives while legally intoxicated (BAC greater than 0.09) = 0.001932
Step-by-step explanation:
P(BAC=0|Crash with fatality)=0.625
P(BAC is between .01 and .09|Crash with fatality)=0.302
P(BAC is greater than .09|Crash with fatality)=0.069
Let the event of BAC = 0 be X
Let the event of BAC between 0.01 and 0.09 be Y
Let the event of BAC greater than 0.09 be Z
Let the event of a crash with at least one fatality = C
P(X|C) = 0.625
P(Y|C) = 0.302
P(Z|C) = 0.069
P(C) = 0.028
probability of a crash with at least one fatality if a driver drives while legally intoxicated (BAC greater than 0.09) = P(C n Z)
But note that the conditional probability of probability that a driver is intoxicated (BAC greater than 0.09) given that there was a crash that involved at least a fatality is given by
P(Z|C) = P(Z n C)/P(C)
P(Z n C) = P(Z|C) × P(C) = 0.069 × 0.028 = 0.001932
Hope this Helps!!!
0.21951 Reapeating cause the decimal does not terminate
Which ever answer you have that has 6 dots in the middle
Answer:
2x+2
Step-by-step explanation:
of symbols, representing a value, o relation. example 2+2=4
Move each point 3 spaces to the right and connect the dots
