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guajiro [1.7K]
3 years ago
14

This is sliding a given figure in a certain direction

Mathematics
1 answer:
saul85 [17]3 years ago
6 0
Counfusing dont know sorry
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Help me how to do this please
Alborosie
The answer is A. C=0 and + = 3
6 0
3 years ago
The bottom of the dais jewelry box of the rectangle with length of 5 3/8 inch in width of 3 and 1/4 in what is the area of the b
lesantik [10]

Answer:The area of the bottom of the jewelry box is 139.75 inch^2

Step-by-step explanation:

The area of a rectangle is expressed as

Area = Length × width

The length of the rectangular bottom of dais jewelry box is 5 3/8 inch. Converting to improper fraction, it becomes 43/8 inch.

The width of the rectangular bottom of dais jewelry box is 3 1/4 inch. Converting to improper fraction, it becomes 13/4 inch.

The area of the bottom of the jewelry box will be

43/8 × 13/4 = 559/32 = 139.75

7 0
3 years ago
Airplane tickets to Fairbanks Alaska, will cost $958 each. Airplane tickets to Vancouver but I will call $734. How much can a fo
Over [174]
4 Tickets to alaska will cost 3832$. 4 Tickets to Vancouver however will cost 2938$. 3832$ - 2938$ = 894$. They will save 894$
8 0
3 years ago
Which of the following expressions correctly uses exponents to show the prime factorization of 360
Andrei [34K]
The prime factorization of 360:

360 = 2·2·2·3·3·5 = 2³ · 3² · 5
5 0
3 years ago
Read 2 more answers
In 2015, Oklahoma experienced 907 perceptible earthquakes (far surpassing California), for an average of about 2.5 perceptible e
Rufina [12.5K]

Answer:

The probability P of a day with no perceptible earthquakes is 0.0821.

Step-by-step explanation:

We will consider that earthquakes occurring in a day is a <u>Poisson process</u>. The following Poisson probability distribution formula will be used in this question.

<u>p(x,λ) = [e^-λ (λ)ˣ]/x!</u>

where x = number of outcomes occurring

           λ = mean number of occurrences

(a) So, in this question we have λ = 2.5 and we need to find the probability that x=0 (no perceptible earthquakes in a day). So,

P(X=0) = p(0,2.5) = [(e^-2.5)(2.5)⁰]/0!

                            = ((0.0821)*1)/1

P(X=0) = 0.0821

The probability P of a day with no perceptible earthquakes is 0.0821.

6 0
3 years ago
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