Answer:
public static double areaSum(Circle c1, Circle c2){
double c1Radius = c1.getRadius();
double c2Radius = c2.getRadius();
return Math.PI * (Math.pow(c1Radius, 2) + Math.pow(c2Radius, 2));
public static void main(String[] args){
Circle c1 = new Circle(6.0);
Circle c2 = new Circle(8.0);
areaSum(c1,c2);
}
Explanation:
Answer:
Its a good game but an amazing show. 10/10
Explanation:
Answer:
Replace text as you type.
Explanation:
Replace text as you type is the Autocorrect option that enables you to add and delete words that do not follow abbreviation rules. This tool is available under the PROOFING tab. For example, if you use a long phrase frequently, simply add it to the replace text as you type. For instance, if you type your address frequently, add 34 Willoughby Street, London, and abbreviate it to 34WS and it was replace it to the long phrase as you type 34WS.
Answer:
The answer to the given question can be given as:
The value of *iptr is 7. and the value of iptr is dynamic.
Explanation:
In the c++ code, it is defined that x is an integer variable that assigns a value which is 7. Then we define a pointer variable that is *iptr. This variable holds an address of the x variable. When we print the value of the iptr variable. if we use the expression *iptr to print value of the pointer variable by cout that is used in c++ for pint values. so the value of the iptr is 7. If we use the expression iptr sent to cout so we show the address of the variable x. In the pointer, it manages the addresses of dynamically allocated so the address of the variable is changed on execution time.
