Answer:
Distance of the keys on ground from the base of the tower = 7.38 ft
Step-by-step explanation:
Given:
Height of tower = 94 ft
Tower is leaning and makes an angle of 85.5 degrees from the ground.
Keys are dropped from the top of the tower.
To find the distance of the keys on ground from the base of the tower.
From the data given to us we can construct a right triangle ABC.
For the Δ ABC
AB= 94 ft
∠A= 85.5°
We can apply trigonometric ratio to find side BC which is the distance of the keys on ground from the base of the tower.
Using cosine ratio: 
In Δ ABC
Multiplying both sides by AB.
Substituting value of AB and cos 85.5°
∴ 
Distance of the keys on ground from the base of the tower = 7.38 ft
Answer:
Area = 270π inches squared. Volume = 550π inches cubed
Step-by-step explanation:
Surface Area:
Cylinder Area=2πrh+2πr^2= 180π+50π=230π inches squared.
Cone Area = πr(r+√(h^2+r^2)) = 5π(18) = 90π inches squared.
Total Area = 230π+90π = 320π inches squared.
Total Area - base = 320π-50π = 270π inches squared.
Volume:
Cylinder volume = πr^2h = 450π inches cubed
Cone volume = πr^2(h/3) = 100π inches cubed
Total Volume = 550π inches cubed
1. So first of all we have to divide the 3 fractions into decimals to get a decimal to compare. So 5/6 is the same as 5 divided by 6 which is .83 bar and so on...
5/6= .83 bar
1/4= .25
2/3= .66 bar
So 5/6 and 2/3 are closer to one.
2. The two shortest pieces are 2/3 and 1/4 so you se 1/4 + 2/3. Let’s get a common denominator for these fractions. The common denominator is 12. So multiply 1/4 • 3 to get 3/12 and multiply 2/3 by • 4 to get 8/12. Add them together and you get 11/12. So he would need 1/12 more cable or 0.083 bar.
3. Now we have to find a common denominator for all of them. The common denominator is 12 again. Multiply 5/6•2 and then you get 10/12, then add 10/12 +2/12(from 1/4) and then you get leftover with 9/12 or 3/4 more wire.
Consider angle XZY in the attached figure. It is always 1/2 the measure of arc XY, no matter where Z may be located on the major arc XZY. This is true even when ZY is very short.
Now, consider what happens when Z falls on top of tangent point Y. The angle is still half the measure of arc XY, still 62°.
Selection C is appropriate.
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I apologize for any confusion caused by my choice of Z as the name of the point I added. Nothing in my explanation is intended to refer to the Z already shown in the unmodified figure.
