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2 years ago

Select ALL of the expressions that are 27 equivalent (equal) to: 27/-3

Mathematics

1 answer:

Rzqust [24]2 years ago

7 0

$\implies {\blue {\boxed {\boxed {\purple {\sf {(2).\: \: \frac{ - 27}{3}\:and\: (5).\: - 9 }}}}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

$\frac{27}{ - 3}$

2. $\: \frac{ - 27}{3}$ ✔

5. $- 9$ ✔

$\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Mystique35♨}}}}}∘$

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A cylindrical pail that has the base area of 9 pi inches squared and a height of 10 inches. One friend bought a pyramid mold wit

FromTheMoon [43]

Answer:

cylinder — 90π in³
pyramid — 37 1/3 in³
cone — 12.5π in³

Step-by-step explanation:

The volume of a cylinder is given by ...

V = Bh . . . . . where B is the base area and h is the height

The volume of a pyramid or cone is given by ...

V = (1/3)Bh . . . . . where B is the base area and h is the height

The area of a square of side length s is ...

A = s²

The area of a circle of radius r is ...

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Using these formulas, the volumes of these objects are ...

cylinder: (9π in²)(10 in) = 90π in³

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3 0

3 years ago

Consider the quadratic function f(x) = x2 – 5x + 12. Which statements are true about the function and its graph? Select three op

klasskru [66]

The graph of the quadratic function f(x)=x² - 5x + 12 is a parabola which opens up.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

The standard form of a quadratic equation is:

y = ax² + bx + c

The graph of a quadratic equation is a parabola.

The graph of the quadratic function f(x)=x² - 5x + 12 is a parabola which opens up.

Find out more on equation at: brainly.com/question/2972832

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4 0

1 year ago

Given the functionf ( x ) = x^2 + 7 x + 10/ x^2 + 9 x + 20

vladimir1956 [14]

<em>x = -4 is a vertical asymptote for the function.</em>

<h2>Explanation:</h2>

The graph of $y=f(x)$ is a vertical has an asymptote at $x=a$ if at least one of the following statements is true:

$1) \ \underset{x\rightarrow a^{-}}{lim}f(x)=\infty\\ \\ 2) \ \underset{x\rightarrow a^{-}}{lim}f(x)=-\infty \\ \\ 3) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty \\ \\ 4) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty$

The function is:

$f(x)=\frac{x^2+7x+10}{x^2+9x+20}$

First of all, let't factor out:

$f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20} \\ \\ f(x)=\frac{x(x+5)+2(x+5)}{x(x+5)+4(x+5)} \\ \\ f(x)=\frac{(x+5)(x+2)}{(x+5)(x+4)} \\ \\ f(x)=\frac{(x+2)}{(x+4)}, \ x\neq 5$

From here:

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ right: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(-4^{+}+2)}{(-4^{+}+4)} \\ \\ \\ The \ numerator \ is \ negative \ and \ the \ denominator \\ is \ a \ small \ positive \ number. \ So: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=-\infty$

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ left: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(-4^{-}+2)}{(-4^{-}+4)} \\ \\ \\ The \ numerator \ is \ a \ negative \ and \ the \ denominator \\ is \ a \ small \ negative \ number \ too. \ So: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=+\infty$