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vagabundo [1.1K]
3 years ago
15

Select ALL of the expressions that are 27 equivalent (equal) to: 27/-3

Mathematics
1 answer:
Rzqust [24]3 years ago
7 0

\implies {\blue {\boxed {\boxed {\purple {\sf {(2).\: \:  \frac{ - 27}{3}\:and\: (5).\: - 9 }}}}}}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

\frac{27}{  - 3}

2. \:  \frac{ - 27}{3} ✔

5. - 9 ✔

\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Mystique35♨}}}}}∘

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What are the fourth roots of 6+6√(3i) ?
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Answer:

Step-by-step explanation:

The genral form of a complex number in rectangular plane is expressed as z = x+iy

In polar coordinate, z =rcos ∅+irsin∅ where;

r is the modulus = √x²+y²

∅ is teh argument = arctan y/x

Given thr complex number z = 6+6√(3)i

r = √6²+(6√3)²

r = √36+108

r = √144

r = 12

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∅ = arctan √3

∅ = 60°

In polar form, z = 12(cos60°+isin60°)

z = 12(cosπ/3+isinπ/3)

To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)

z^1/4  = 12^1/4(cosπ/12+isinπ/12)

When n = 1;

z1 =  12^1/4(cosπ/3+isinn/3)

z1 = 12^1/4cis(π/3)

when n = 2;

z2 = 12^1/4(cos2π/3+isin2π/3)

z2 = 12^1/4cis(2π/3)

when n = 3;

z2 = 12^1/4(cosπ+isinπ)

z2 = 12^1/4cis(π)

when n = 4;

z2 = 12^1/4(cos4π/3+isin4π/3)

z2 = 12^1/4cis(4π/3)

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