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igomit [66]
2 years ago
13

The researchers introduced a small RNA complementary to a portion of the mRNA encoding protein A into the Brec-MUT cells growing

in a petri dish. The researchers claim that the treated cells will fail to stimulate blood vessel formation. Based on information provided, provide reasoning to support their claim.
Biology
1 answer:
Sonbull [250]2 years ago
3 0

Answer:

Delivered small RNAs can inhibit protein A production through the RNA interference (RNAi) mechanism, and thus impairs angiogenesis  

Explanation:

The pregnancy-associated plasma protein-A is a protease enzyme involved in the formation of new blood vessels by increasing insulin-like growth factor I (IGF-I) bioavailability. Moreover, small RNAs (<200 nucleotides in length, generally 18 to 30 nucleotides) are non-coding RNA molecules that function in RNA silencing through the RNA interference (RNAi) pathway. Small RNAs are widely used in molecular biology laboratories because they can be delivered into specific cells in order to silence target mRNAs such as, in this case, the mRNA encoding protein A, by complementary base pairing and thereby inducing translational repression. In consequence, mRNAs complementary to delivered small RNAs are silenced through RNAi pathways, i.e., by cleavage of the target mRNA and/or mRNA destabilization.

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Monica [59]

Answer:

The answer is Small intestine

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7 0
3 years ago
1. Excretion is the process of (1 point)
alex41 [277]
The right answer for the question that is being asked and shown above is that: (1) removing metabolic wastes from the body; (2) urea is not soluble in water; (3) simple diffusion across the skin; (4) They both actively pump salt across their gills; (5) <span>They both produce lots of diluted urine."</span>
8 0
2 years ago
Read 2 more answers
A biologist has been studying two populations of trout in Montana for the last 25 years, when the two populations were establish
ludmilkaskok [199]

Answer:

Positive natural selection.

Explanation:

The positive natural selection is a type of natural selection that increases the frequency of an allele or trait when it is advantageous for the population. What happened in the example is that the mouth with the slight change in  morphology (trait)  was more advantageous for the population in the south in relation to the  ancestral morphology  (still preserved in the population in the north), and therefore its frequency increased. This, in turn, is due to the fact that the food (prey) is not the same in the two habitats (north and south).  The specific prey in the south,  caused the new morphology to be selected, (increasing the frequency of individuals with the new mouth),  becasue probably that trait allows the trouts in the south to hunt more effectively.

8 0
3 years ago
explain how repressible and inducible operons differ and how those differences reflect differences in the pathways they control
Sonja [21]

Answer

Operons are cluster of coordinated genes, including structural genes, an operator gene, and a regulatory gene.

Explanation:

In the The repressible operons, The transcription is usually on and repressor is in inactive form, So the specific genes are transcribed. While a regulatory molecule act as corepressor and binds to repressor protein to activate it. The repressor protein cause the inactivation of repressible operon (as the name indicate). E.g., Tryptophan Repress the trp operon.

A high level of product act as regulatory molecule (Corepressor) and turn off the operon, So anabolic pathways or synthesis of essential components are controlled by repressible operon.

In the Inducible operons, the transcription is usually off and repressor is in active form. So there is no transcription of genes. Specific Metabolite cause the activation of operon  e.g lactose cause the induction of lac operon.

As a metabolite induces the operon, So they control the Metabolic pathways or breakdown of a neutrient.

7 0
3 years ago
Hershey and Chase used radioactive isotopes to label different parts of the phage. They grew one batch of phage in the presence
AlekseyPX

The sulphur would lable the capsule and the phosphorous the nucleic acid.

<h3><u>Explanation</u>:</h3>

Hershey and Chase experiment included growing of the pages in two batches, one in presence of 35S and other in presence of 32P. They then infected bacterial cells with these phages, cleaned them and then centrifuge the cells to isolate the marked elements in bacterial cells.

This was done to isolate which part of the phage is actually infective. Sulphur being a part of the proteins will mark the capsule whereas DNA having the phosphate bridges will be marked by 32P.

5 0
3 years ago
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