All categories

3 years ago

Which measurements could not represent the side lengths of a right triangle?

Mathematics

1 answer:

victus00 [196]3 years ago

5 0

Answer: C

Step-by-step explanation: a^2 + b^2 = c^2

A. 6^2 + 8^2 = 10^2

B. 12^2 + 35^2 = 37^2

C. 4^2 + 6^2 does not equal 10^2.....(16 + 36 = 52 10^2 = 100)

D. 10^2 + 24^2 = 26^2

You might be interested in

How many soulutions does -2(6-3x)=-12+6x have ?

Natalija [7]

Answer:

Step-by-step explanation:

Only one

5 0

3 years ago

30 points please help urgent

BlackZzzverrR [31]

x = 2

x = 50

HOPE THIS WILL HELP YOU

7 0

4 years ago

Please help! Will mark brainliest

kobusy [5.1K]

Answer:

B. 15"

Step-by-step explanation:

$a^{2}+b^2=c^2\\9^2+12^2=c^2\\81+144=c^2\\225=c^2\\\sqrt{225} = 15$

7 0

3 years ago

The interior dimensions of Sals refrigerator are 5 ft by 2 1/2 Ft by 2 ft. Find the capacity (Volume) of the refrigerator in cub

Stella [2.4K]

Answer:

I think its 5 and 4 are the answer

8 0

3 years ago

How do I get this answer?

Keith_Richards [23]

Answer:

Step-by-step explanation:

Several trig identities are involved in the proof of this. This is the order in which they are used.

cos(2x) = cos²(x) -sin²(x)
cos²(x) +sin²(x) = 1
cos(x) = 1/sec(x)

<h3>Proof</h3>

Starting with the left side, we can transform it into the right side.

$2\cos(2x)=2(\cos^2(x)-\sin^2(x)) = 2(\cos^2(x)-(1-\cos^2(x)))\\\\=2(2\cos^2(x)-1)=2\left(\dfrac{2}{\sec^2(x)}-\dfrac{\sec^2(x)}{\sec^2(x)}\right)\\\\=\boxed{\dfrac{4-2\sec^2(x)}{\sec^2(x)}}$

4 0

2 years ago