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2 years ago

Which measurements could not represent the side lengths of a right triangle?

Mathematics

1 answer:

victus00 [196]2 years ago

5 0

Answer: C

Step-by-step explanation: a^2 + b^2 = c^2

A. 6^2 + 8^2 = 10^2

B. 12^2 + 35^2 = 37^2

C. 4^2 + 6^2 does not equal 10^2.....(16 + 36 = 52 10^2 = 100)

D. 10^2 + 24^2 = 26^2

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Megan received a $208,000 inheritance after taxes from her parents. She invested it at 8% interest compounded quarterly for 5 ye

Nookie1986 [14]

Use the compound interest formula.
A = P*(1 +r/n)^(n*t)
where P is the principal, r is the annual rate, n is the number of compoundings per year, and t is the number of years.

For the first investment, ...
A = 208,000*(1 +.08/4)^(4*5) = 309,077.06

For the second investment, ...
A = 218,000*(1 +.07/2)^(2*4) = 287,064.37

Totaling both investments at maturity, Megan has $596,141.43.

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3 years ago

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8090 [49]

help

okay so first add help the subtract help help finally dividing the help^2 equally help/help

3 0

3 years ago

Read 2 more answers

Scores on the SAT Mathematics test are believed to be normally distributed. The scores of a simple random sample of five student

AysviL [449]

Answer:

The mean calculated for this case is $\bar X=584$

And the 95% confidence interval is given by:

$584-2.776\frac{86.776}{\sqrt{5}}=476.271$

$584+2.776\frac{86.776}{\sqrt{5}}=691.729$

So on this case the 95% confidence interval would be given by (476.271;691.729)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=584$

The sample deviation calculated $s=86.776$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that $t_{\alpha/2}=2.776$

Now we have everything in order to replace into formula (1):

$584-2.776\frac{86.776}{\sqrt{5}}=476.271$

$584+2.776\frac{86.776}{\sqrt{5}}=691.729$

So on this case the 95% confidence interval would be given by (476.271;691.729)

3 0

2 years ago

What is the value of x in the equation 3x - 4y=65, when y=4?<br> N

4vir4ik [10]

Answer:

x =27

Step-by-step explanation:

3x - 4y=65

lets substitute the value of y in the equation:

3x -4(4) =65

3x = 65 +16

3x= 81

x= 81/3

x = 27

3 0

3 years ago

Classify the scenarios based on whether they are observational studies, experiments, or surveys. Scenario A: Twenty employees of

viktelen [127]

Answer:

Just took test, got it right. In the following:

Step-by-step explanation:

Scenarios:

A- Survey

B- Observation

C- Experiment

D- Survey

6 0

2 years ago