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krek1111 [17]
3 years ago
7

Which measurements could not represent the side lengths of a right triangle?

Mathematics
1 answer:
victus00 [196]3 years ago
5 0

Answer: C

Step-by-step explanation: a^2 + b^2 = c^2

A. 6^2 + 8^2 = 10^2

B. 12^2 + 35^2 = 37^2

C. 4^2 + 6^2 does not equal 10^2.....(16 + 36 = 52   10^2 = 100)

D. 10^2 + 24^2 = 26^2

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In article <[email protected]>,
[email protected] (Hauke Reddmann) wrote:

<span>> Let a*x**3+b*x**2+c*x+d=0 have a double and a single root.
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2 3
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----------------------------------
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<span>or any other expression equivalent under </span>

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Maple verification:

> f:=a*x^3+b*x^2+c*x+d;
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dis := a (27 d a + 4 b d - 18 c a d b - b c + 4 c a)

>
factor(subs(x=d*(-9*d^2*a+4*d*b*c-c^3)/(6*d^2*c*a+4*d^2*b^2-5*b*c^2*d+c^4),f));

3 4 2 3 2 3 3 3 2 2 2 4
d (-27 d a + 36 d a b c - 9 d a c + 16 d b - 24 d b c + 9 d b c

6 2 2 3 2 2 3 /
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/

2 2 2 2 4 3
(6 d c a + 4 d b - 5 b c d + c )


<span>> (Bonus points if it's possible to write the answer without
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Impossible, multiplying all a,b,c,d by the same factor lambda should
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<span>--</span>
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