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Distance: 7-(-3)=10 Midpoint: (7+(-3))=4/2=2 hahaha haha thats right
Answer:
0
Step-by-step explanation:
Assuming the problem is:
"lim x-> 4 f(x)=5 lim x-> 4 g(x)=0 and lim x-> 4 h(x)=-2, then find lim x->4 (fg)(x)"
lim x->4 (fg)(x)
Since we know the limits of f and g at x=4 exist we can write the limit as:
lim x->4 f(x) lim x->4 g(x) (since fg(x) means f times g of x.)
5(0)
0
Answer:
2
Step-by-step explanation:
No; we have 
. Substituting these into the DE gives
which reduces to 
, true only for 
.
