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liraira [26]
3 years ago
14

Un avión puede volar con la velocidad de 400 km por hora en atmósfera tranquila si cuando se dirige hacia el este el viento vien

e del Sur con la velocidad de 40 km por hora cuál es la dirección de su vuelo
Mathematics
1 answer:
Bumek [7]3 years ago
3 0

Answer:

84,3 ° Sureste

Step-by-step explanation:

El diagrama vectorial que tipifica la pregunta se muestra en la imagen adjunta.

La dirección del avión es la dirección de la velocidad resultante.

Si esta dirección es θ

θ = tan ^ -1 (400/40)

θ = 84,3 ° Sureste

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Factor Trinomials:
notka56 [123]

Answer:

1. 2(x+2)(x+5)

2. 8(x+4)^{2}

Step-by-step explanation:

<u>Problem #1:</u>

1. Find the GCF (Greatest Common Factor)

GCF = 2

2. Factor out the GCF and simplify.

2(x^{2} +7x+10)

3. Factor x^{2} +7x+10

<u>Which two numbers add up to 7 and multiply to 10?</u>

2 and 5

<u>Rewrite the expression using the above.</u>

(x+2)(x+5)

4. Done!

2(x+2)(x+5)

<u>Problem #2:</u>

1. Find the GCF (Greatest Common Factor)

GCF=8

2. Factor out the GCF and simplify.

8(x^{2} +8x+16)

3. Use the perfect square formula. a^{2} +2ab+b^{2} =(a+b)^{2}

a = x\\b=4

(x+4)^{2}

4. Done!

8(x+4)^{2}

8 0
2 years ago
A horse's mane grows at the rate of 6/5 centimeters per month. How many months will it take the horse's mane to grow 24/10 centi
Fittoniya [83]
24/10
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6/5

2 months
6 0
3 years ago
The ratio of boys to girls at King Middle school is 3:2. What is the ratio of girls to all students?
Dominik [7]
The answer is:  " 2 :5 " ;  or, write as:  " 2/5 " . 
________________________________________________________
The ratio of 'girls' to 'all students' is:  "2: 5 " ;  or, write as:  " 2/5 ".
________________________________________________________
Explanation:
________________________________________________________
Given:  The ratio of boys to girls is:  " 3:2 " .  

Problem:  Find the ratio of "girls" to "all students:
________________________________________________________
Note:    This ratio of "boys to girls", which is " 3 : 2 " ; 
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    →  can be expressed as " 3x: 2x"  ;  

in which the total number of students is:  " 3x + 2x " = 5x " .

   → The total number of students is represented as:  " 5x " .  
________________________________________________________
→  The ratio of "girls to boys" is:  "2x : 3x" .

→  {that is;  the "inverse" of the ratio of "boys to girls"} ;  
→  {that is;  the "inverse" of  " 3x: 2x" } ;  →  which is:  " 2x : 3x " .
________________________________________________________ 

The ratio of "girls" to "all students" is:  "2x : 5x "  ;  or " 2x/5x " ; 
                                             → Both "x" values cancel ;  {since: " x/x = 1 "} ; 
_________________________________________________________
       →  and we have the answer:  " 2 :5 " ;  or, write as:  " 2/5 " . 
_________________________________________________________
The ratio of 'girls' to 'all students' is:  " 2 :5 " ;  or, write as:  " 2/5 ".
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8 0
3 years ago
How do I solve: 3w/x=6e
lana [24]
The answer is ×=w/2e.thats it
7 0
3 years ago
jenna's rectangular garden borders a wall. she buys 80 ft of fencing. what are the dimensions of the garden that will maximize i
FrozenT [24]

Answer:

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

Step-by-step explanation:

Step 1:-

let 'x' be the length  and the 'y' be the width of the rectangle

given Jenna's buys 80ft of fencing of rectangle so the perimeter of the rectangle is    2(x +y) = 80

                         x + y =40

                               y = 40 -x

now the area of the rectangle A = length X width

                                                  A = x y

substitute 'y' value in above A = x (40 - x)

                                              A = 40 x - x^2 .....(1)

<u>Step :2</u>

now differentiating equation (1) with respective to 'x'

                                      \frac{dA}{dx} = 40 -2x     ........(2)

<u>Find the dimensions</u>

<u></u>\frac{dA}{dx} = 0<u></u>

40 - 2x =0

40 = 2x

x = 20

and y = 40 - x = 40 -20 =20

The dimensions are x =20 and y=20

length = 20 and breadth = 20

<u>Step 3</u>:-

we have to find maximum area

Again differentiating equation (2) with respective to 'x' we get

\frac{d^2A}{dx^2} = -2

Now the maximum area A =  x y at x =20 and y=20

                                        A = 20 X 20 = 400

                                         

<u>Conclusion</u>:-

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

<u>verification</u>:-

The perimeter = 2(x +y) =80

                           2(20 +20) =80

                              2(40) =80

                              80 =80

8 0
3 years ago
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