Write an equation for the line described. Give the answer in standard form. through (2,6), m= -5
1 answer:
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Answer:
5x +y = 16
Step-by-step explanation:
Given a point and slope, it often works well to start with the point-slope form of the equation for a line:
y -k = m(x -h) . . . . . . . . line with slope m through point (h, k)
Your point and slope make this ...
y -6 = -5(x -2)
y -6 = -5x +10 . . . . . . eliminate parentheses
5x +y = 16 . . . . . . . . . add 5x+6 to both sides; your standard form equation
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Answer:
Point-slope form of equation given as .
Slope-intercept form of equation is given as .
Step-by-step explanation:
In the question, it is given that the slope of a line is -2 and it passes from (-2,2).
It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.
To do so, first find the values which are given in the question and put it in the formula of point-slope form. Simplify the equation to rewrite as slope-intercept form.
Step 1 of 2
Passing point of the line is (-2,2).
Hence, and
Also, the slope of the line is -2.
Hence, m=-2
Substitute the above values in point-slope form of equation given by
Hence, point-slope form of equation given as y-2=-2(x+2).
Step 2 of 2
Solve y-2=-2(x+2) to write it as slope-intercept form given by y=mx+c.
Hence, slope-intercept form of equation is given as y=-2x-2.