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JulijaS [17]
3 years ago
7

Mary French uses gas to heat her home. She has accumulated the following information regarding her monthly gas bill and monthly

heating degree-days. The heating degree-days value for a month is found by first subtracting the average temperature for each day from 65 degrees and then summing these daily amounts together for the month. Month Heating Degree-Days Gas Bill February 1,900 $195 April 600 $78 The equation representing the relationship between the gas bill (Y) and heating degree-days (X) is:
Mathematics
1 answer:
garik1379 [7]3 years ago
7 0

Answer:

Y=$24+0.09X

Step-by-step explanation:

From the question we are told that

February Heat H_1=1900\textdegree

February Gas G_1 =\$195

April Heat H_2=600\textdegree

April Gas G_2=\$78

Generally equation for heating degree-days X is mathematically given by

 X=\frac{\triangle gas\ bills}{\triangle Heating\ days}

 X=\frac{195-78}{1900-600}

 X=\$ 0.09

Generally the equation for gas bill Y is mathematically represented by

 Y=78-(600*0.09)\\Y=\$24

The equation representing the relationship between the gas bill (Y) and heating degree-days (X) is

 Y=$24+0.09X

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Helppppppppppppp. a and b partttt​
PilotLPTM [1.2K]

Answer:

a) 220.17 cm

b) 2127.12 cm²

Step-by-step explanation:

perimeter = circumference

it is the sum of the inner and the outer arc and the 2 side lines of 25.

we know a full circle has 360 degrees. but we only look at a segment of a circle of 150 out of the total of 360 degrees.

the circumference of a circle is

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the 150 degree part is then

C = 2×pi×r×150/360 = 2×pi×r×15/36 = pi×r×15/18 =

= pi×r×5/6

the radius of the inner circle is 20.

=>

Ci = pi×20×5/6 = pi×50/3

the radius of the outer circle is 20 + 25 = 45

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so, the total perimeter/ circumference is

C = Ci + Co + 25 + 25 = pi×50/3 + pi×75/2 + 50

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the area of the shaded shape is the area of the large circle segment minus the area of the small circle segment.

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A = pi×r²

the 150 degree part is then

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so, for the inner circle that is

Ai = pi×20²×5/12 = pi×400×5/12 = pi×100×5/3 = pi×500/3

for the outer circle that is

Ao = pi×45²×5/12 = pi×2025×5/12 = pi×10125/12 =

= pi×3375/4

so, the total area of the shaded shape is

A = Ao - Ai = pi×3375/4 - pi×500/3 = pi×(10125-2000)/12 =

= pi×8125/12 = 2127.12 cm²

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