Answer:
what is your question friend? :)
Answer:
The answer is below
Step-by-step explanation:
The distance traveled the first day = Distance from San Jose to Santa Barbara = 320 mile.
The distance traveled the second day = Distance from Santa Barbara to Los Angeles.
But From San Jose to Los Angeles = 425 mile. Therefore:
Distance From San Jose to Los Angeles = Distance from San Jose to Santa Barbara + Distance from Santa Barbara to Los Angeles
425 = 320 + Distance from Santa Barbara to Los Angeles.
Distance from Santa Barbara to Los Angeles = 425 - 320 = 105 mile
The distance traveled the second day = Distance from Santa Barbara to Los Angeles = 105 miles
The distance traveled the first day + The distance traveled the second day = Distance from San Jose to Santa Barbara + Distance from Santa Barbara to Los Angeles = 320 + 105 = 425 miles
The distance traveled the first day + The distance traveled the second day = 425 miles
we know that
m∠PTS=m∠RTQ -----> by vertical angles
Step 1
m∠RTQ+m∠QTS=
-------> by supplementary angles
solve for m∠QTS
m∠QTS=-m∠RTQ -------> equation 
Step 2
m∠PTS+m∠QTS= -------> by supplementary angles
solve for m∠QTS
m∠QTS=-m∠PTS -------> equation 
Step 3
equate equation and equation
-m∠RTQ=-m∠PTS
-m∠RTQ=-m∠PTS
so
m∠RTQ=m∠PTS
therefore
<u>the answer is the option A</u>
Sum of the measures of angles RTQ and QTS is 180°
tangent(angle) = Opposite Leg ( Height) / Adjacent Leg ( base)
Tangent(56.3) = Opposite Leg / 48 feet
Opposite Leg = 48 x tangent(56.3) = 71.97
Height = 72 feet ( rounded to the nearest foot).
Answer:
A and C
<em>I hope this helps! ^^</em>
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