Evaluate. −64125−−−−√3
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Answer:
519
Step-by-step explanation:
Let's assume that the scores for the national verbal proficiency test follow a normal distribution.
Mean score (μ) = 500
Standard deviation (σ) = 75
According to a Z-score table, the score for the 60th percentile is roughly z = 0.253
For any score "x", the z-score is given by:
For z = 2.53:
The raw score to the 60th percentile is 519.