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3 years ago

Pls help. I need it asap

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

3 0

Answer:

Step-by-step explanation:

since the equation of AC is y=x-4 then the length of CB and AB must be the same. therefor its (6*6)/2

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A right triangle has side lengths d, e, and f as shown below.

DIA [1.3K]

Answer:

and f as shown below.

Use these lengths to find cosx, sinx, and tanx.

Step-by-step explanation:

5 0

3 years ago

Show that: (p¼- q¼)(p¼ + q¼)(√P+√q)= p-q.

Irina18 [472]

Answer:

Step-by-step explanation:

let p¼ = a, q¼ = b

L.H.S. = (a - b)(a + b)(a² + b²) = (a² - b²)(a² + b²) = (a²)² - (b²)² = p - q = R.H.S.

3 0

2 years ago

Read 2 more answers

Hopefully that’s better :)))

mr Goodwill [35]

Answer: Top right, a rectangle has all the properties of a square

Step-by-step explanation: A rectangle does not have all the properties of a square.

8 0

3 years ago

2m=p-q/r solve for r

Oduvanchick [21]

To solve for r, you would start by subtracting p from both sides.

2m - p = -q/r

Multiply everything by r.

2mr - pr = -q

Factor r out of the left side of the equation.

r(2m - p) = -q

Divide both sides by (2m - p).

r = $\frac{-q}{2m-p} = \frac{q}{2m + p}$ .

6 0

3 years ago

WILL GIVE BRAINLIEST& 15 PTS.

kicyunya [14]

Answer:

The given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

Step-by-step explanation:

Consider the given fraction $\frac{x^3-x^2}{x^3}$

We have to reduce the fraction to the lowest terms.

Consider numerator $x^3-x^2$

We can take x² common from both the term,

Thus, numerator can be written as $x^2(x-1)$

Given expression can be rewritten as ,

$\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}$

We can now cancel $x^2$ from both numerator and denominator,

$\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}$

$\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}$

Thus, the given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

6 0

3 years ago

Read 2 more answers