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2 years ago

Pls help. I need it asap

Mathematics

1 answer:

Amiraneli [1.4K]2 years ago

3 0

Answer:

Step-by-step explanation:

since the equation of AC is y=x-4 then the length of CB and AB must be the same. therefor its (6*6)/2

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4/r=5/7solve for r. Help pls

antiseptic1488 [7]

Hello!

You first cross multiply

4 * 7 = 28

5 * r = 5 * r

r * 5 = 28

Divide both sides by 5

r = 28/5 = 5.6

The answer is 28/5 or 5.6

Hope this helps!

4 0

2 years ago

Read 2 more answers

How many different four-digit numbers can be made using the digits 1,2,3,4,5,6 if no digit can be used more than once?

igomit [66]

Answer:

360

Step-by-step explanation:

The given digits are 1,2,3,4,5,6.

So, total number of digits = 6.

We need to find the number of different ways to form four-digit numbers using the digits, without repetition.

Total ways for first place = 6

After selecting 1 digit the number of remaining digits is 5. So,

Total ways for second place = 5

Similarly,

Total ways for third place = 4

Total ways for forth place = 3

Total number of ways = $6\times 5\times 4\times 3=360$

Therefore, 360 four digit numbers are possible.

5 0

2 years ago

Use FOIL to explain how to find the product of (a + b)(a − b). Then describe a shortcut that you could use to get this product w

xenn [34]

Answer:

The product of (a+b)(a-b) is $a^2 - b^2$

Step-by-step explanation:

Use FOIL to explain how to find the product of (a + b)(a − b)

FOIL is

Multiply First terms : a*a = a^2

Multiply Outside terms : a* -b = -ab

Multiply Inner terms : b * a= ab

Multiply last terms : b * -b = -b^2

now we combine all the terms

$a^2 -ab+ab - b^2$

combine like terms

$a^2 - b^2$

The product of (a+b)(a-b) is $a^2 - b^2$

Shortcut is we apply an identity

$a^2 - b^2 = (a+b)(a-b)$

8 0

2 years ago

Read 2 more answers

Choose all values of a that make the following equation true: 3/4 = a/36.

Gekata [30.6K]

9514 1404 393

Answer:

B, D

Step-by-step explanation:

The equation can be solved by multiplying by 36.

3/4 = a/36

a = 36(3/4) = 108/4 = 27

The listed values that make the equation true are 27 and 108/4.

4 0

3 years ago

A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a

sineoko [7]

ANSWER

The scale factor is
$2.5$

EXPLANATION

The given triangle has vertices,

$A(0,0),B(0,4),\:and\:C(6, 0)$ .

The vertices of the image triangle is,

$A'(0,0),B'(0,10),\:and\:C'(15, 0)$ .

The scale factor is given by

$k = \frac{image \: length}{object \: length}$

So we can use any of the corresponding sides to determine the scale factor,

$k = \frac{|A'B'|}{ |AB|}$

$k = \frac{ |10 - 0| }{ |4 - 0|}$

$k = \frac{ |10| }{ |4 |} = \frac{10}{4} = 2.5$

Or

$k = \frac{|A'C'|}{ |AC|}$

$k = \frac{ |15 - 0| }{ |6 - 0|}$

$k = \frac{ |15| }{ |6|} = \frac{15}{6} = 2.5$

Or

$k=\frac{|B'C'|}{|BC|}$

$k = \frac{\sqrt{(15 - 0)^2+(0-10)^2 }}{\sqrt{(6 - 0)^2+(0-4)^2}}$

$k = \frac{ 5\sqrt{13}}{2\sqrt{13}} = \frac{5}{2} = 2.5$

The correct answer is C

3 0

2 years ago