Answer:
38 grams
Step-by-step explanation:
7.6*5=38
Base 10 blocks are used to perform arithmetic operations.
To model the product of 3 and 0.51, Evan needs <em>3 copies of 5 tenths and 1 hundredths.</em>
The expression can be represented as:

Express 0.51 as 0.5 + 0.01

- 0.5 means 5 tenths
- 0.01 means 1 hundredths
- 3 means that, the above blocks are needed in three places.
Hence, Evan needs <em>3 copies of 5 tenths and 1 hundredths.</em>
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Read more about base 10 blocks at:
brainly.com/question/7621712
Answer:
Annual gross income = $26,936
Step-by-step explanation:
Given:
Per hour Brianna wages = $18.50
Number of hour per week work = 28 hours
Find:
Annual gross income
Computation:
Number of week in year = 52
Annual gross income = Per hour Brianna wages x Number of hour per week work x Number of week in year
Annual gross income = 18.50 x 28 x 52
Annual gross income = $26,936
<h2>How to find the cost per can</h2>
To find the cost per can, we can divide the total cost by the number of cans.

<h2>
Let's start with BiLo:</h2>
Total cost: $5.55
Number of cans: 12
The cost per can will be:

$0.4625 per can
How about Food Lion?
<h2>Food Lion</h2>
Total cost: $2.75
Number of cans: 6
The cost per can will be:

Around $0.4583 per can
<h2>Comparing</h2>
BiLo: $0.4625
Food Lion: around $0.4583
As we can see, Food Lion has a better cost per can, as it costs less to buy each can of Pepsi.
Answer: Food Lion has a better cost per can
Answer:
The answer is given below
Step-by-step explanation:
The loads in the circuit are continuous duty, so the circuit can only loaded to 80% of its current rating.
Calculate 80% current rating of the circuit breaker.
Icb = [ 80/100] (20 A)
= (O.8) (20 A )
= 16 A
Now we assume that the value of supply voltage is 120 V
Now we will calculate current flows via under water light which will be taken as Load 1
<em>Ii = </em>500 W/120 V
= 4.167 A
Current via the circulating pump which will be taken as Load 2 IS 8.5 A
<em>I = </em>load1 + load 2
<em> = 4.167 A + 8.5 A</em>
<em> = 12.67 A</em>
The total current in the circuit obtained which is less than the circuit breaker rating current. Therefore, the power can be operated for both the loads.