Answer:
a. 8.66 minutes
Step-by-step explanation:
Since the flight times are uniformly distributed, the standard deviation can be calculated as follows:
![\sigma = \frac{b-a}{\sqrt{12}}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Cfrac%7Bb-a%7D%7B%5Csqrt%7B12%7D%7D)
Where '<em>b' </em>is the maximum flight time (150 minutes) and '<em>a' </em>is the minimum flight time (120 minutes):
![\sigma = \frac{150-120}{\sqrt{12}}\\\sigma = 8.66\ minutes](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Cfrac%7B150-120%7D%7B%5Csqrt%7B12%7D%7D%5C%5C%5Csigma%20%3D%208.66%5C%20minutes)
The distribution's standard deviation is 8.66 minutes.
Answer:
About 947 hours, walking at 5 km (3 miles)/hour.
Walking 8 hours /day [at that pace you would need to be an Olympic Athlete to keep up the pace] it will take about four months.
Walk slower, it will take longer.
Answer:
Step-by-step explanation:
56.27 =
50
+ 6
+ 0.2
+ 0.07
Expanded Factors Form:
56.27 =
5 × 10
+ 6 × 1
+ 2 × 0.1
+ 7 × 0.01
Expanded Exponential Form:
56.27 =
5 × 101
+ 6 × 100
+ 2 × 10-1
+ 7 × 10-2
Word Form:
56.27 =
fifty-six and twenty-seven hundredths
Step-by-step explanation:
x = number of multiple choice questions
y = number of short response questions
x + y = 15
5x + 10y = 100
=>
x + 2y = 20
let's subtract the first from the second equation :
x + 2y = 20
- x + y = 15
--------------------
0 y = 5
x + y = 15
x + 5 = 15
x = 10
to graph you need to consider both equations as linear functions. and you need to transform them into e.g. a slope intercept form : y = ax + b
a is the slope, b is the y- intercept.
x + y = 15
transforms to
y = -x + 15
this line goes e.g. through the points (0, 15) and (1, 14).
and
x + 2y = 20
transforms to
2y = -x + 20
y = -x/2 + 10
this line goes e.g through (0, 10) and (2, 9).
the crossing point of both lines is the solution and should therefore be the point (10, 5) as calculated above.
Answer:
![\sqrt{2} (3\sqrt{2} +\sqrt{14})=6+2\sqrt{7}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D%20%283%5Csqrt%7B2%7D%20%2B%5Csqrt%7B14%7D%29%3D6%2B2%5Csqrt%7B7%7D)
Step-by-step explanation:
Given : ![\sqrt{2} (3\sqrt{2} +\sqrt{14})](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D%20%283%5Csqrt%7B2%7D%20%2B%5Csqrt%7B14%7D%29)
Solution:
![\sqrt{2} (3\sqrt{2} +\sqrt{14})](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D%20%283%5Csqrt%7B2%7D%20%2B%5Csqrt%7B14%7D%29)
![3*2+\sqrt{28})](https://tex.z-dn.net/?f=3%2A2%2B%5Csqrt%7B28%7D%29)
![6+2\sqrt{7}](https://tex.z-dn.net/?f=6%2B2%5Csqrt%7B7%7D)
Thus , ![\sqrt{2} (3\sqrt{2} +\sqrt{14})=6+2\sqrt{7}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D%20%283%5Csqrt%7B2%7D%20%2B%5Csqrt%7B14%7D%29%3D6%2B2%5Csqrt%7B7%7D)
Thus the solution is irrational since square root 7 does not have a perfect square and equal to 6+2square root of 14