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sergeinik [125]

3 years ago

9

Does anyone know this ? i'm stuck.. i'll give you brainliest and 15 points !! show work.

1 answer:

madam [21]3 years ago

5 0

Answer:

x = 7

Step-by-step explanation:

The angle adjacent to the 70 degree angle is also 70 degrees. We assume that there are four 90-degree angles in the center of the figure. Thus, 8x - 36 + 70 + 90 = 180 (the sum of the interior angles is 180 degrees).

Solving 8x - 36 + 70 + 90 = 180 for x:

8x - 36 = 20, or 8x = 56.

Dividing both sides by 8 yields x = 7.

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What is the absolute value of the complex number -4-√2

Zepler [3.9K]

|a+bi| = √(a² + b²)

-4-√2 i -> take a = -4 and b = -√2

|-4-√2 i| = √[ (-4)² + (<span>-√2)² ]
               = </span><span>√[ 16 + 2<span> ]
               </span></span><span>= √[ 18 ]</span> = <span>√[ 9 * 2 ]
   = 3√2
the absolute value is 3√2</span>

6 0

3 years ago

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in <u>slope-intercept formula</u>, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of <u>k and m.</u>

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

7 0

2 years ago

What are the solution(s) to the quadratic equation 50 - x² = 0?

grandymaker [24]

Answer:

The answer is C.

Step-by-step explanation:

$50-x^2=0$

$x^2=50$

$x=\pm \sqrt{50} =\pm \sqrt{25*2}=\pm 5\sqrt{2}$

The answer is C (I am assuming that it isn't 5/2).

7 0

3 years ago

621/87 can anybody help me

Ilia_Sergeevich [38]

Answer:

621/87=7.13793103448

Step-by-step explanation:

I divided it and got this answer

5 0

3 years ago

Read 2 more answers

Why do I miss her? :/

Dima020 [189]

Answer:

because you probably liked her or you just miss her company ya know talking with her or just messing around lol

4 0

3 years ago