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Irina18 [472]
3 years ago
15

Write a unit rate for the situation: 2520 kilobytes in 18 seconds

Mathematics
2 answers:
elixir [45]3 years ago
7 0
140 kilobytes per second
Ahat [919]3 years ago
3 0

Answer:

the unit rate is equal to 140 kilobytes/sec

Step-by-step explanation:

A kilobyte per second is the unit of measurement used in computing to measure the speed of transfer of information in a network. To calculate the rate is only to divide the kilobits over time. In general, it can be said that if the network bandwidth is large, the data transmission speed will be larger. The calculation can be done as follows:

2520 kilobytes/18 seconds = 140 kilobytes/sec

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The random variable X is exponentially distributed, where X represents the waiting time to be seated at a restaurant during the
erastova [34]

Answer:

The probability that the wait time is greater than 14 minutes  is 0.4786.

Step-by-step explanation:

The random variable <em>X</em> is defined as the waiting time to be seated at a restaurant during the evening.

The average waiting time is, <em>β</em> = 19 minutes.

The random variable <em>X</em> follows an Exponential distribution with parameter \lambda=\frac{1}{\beta}=\frac{1}{19}.

The probability distribution function of <em>X</em> is:

f(x)=\lambda e^{-\lambda x};\ x=0,1,2,3...

Compute the value of the event (<em>X</em> > 14) as follows:

P(X>14)=\int\limits^{\infty}_{14} {\lambda e^{-\lambda x}} \, dx=\lambda \int\limits^{\infty}_{14} {e^{-\lambda x}} \, dx\\=\lambda |\frac{e^{-\lambda x}}{-\lambda}|^{\infty}_{14}=e^{-\frac{1}{19} \times14}-0\\=0.4786

Thus, the probability that the wait time is greater than 14 minutes  is 0.4786.

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3 years ago
8,minus some number divided by 3, equals 6. find the numbers
algol [13]
8 - (-10) = 18
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Step-by-step explanation:

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