Write a unit rate for the situation: 2520 kilobytes in 18 seconds

Mathematics

2 answers:

elixir [45]3 years ago

7 0

140 kilobytes per second

Ahat [919]3 years ago

3 0

Answer:

the unit rate is equal to 140 kilobytes/sec

Step-by-step explanation:

A kilobyte per second is the unit of measurement used in computing to measure the speed of transfer of information in a network. To calculate the rate is only to divide the kilobits over time. In general, it can be said that if the network bandwidth is large, the data transmission speed will be larger. The calculation can be done as follows:

2520 kilobytes/18 seconds = 140 kilobytes/sec

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<h2>The population will reach 1200 after about 2.8 years</h2>

Step-by-step explanation:

The question is incomplete. Here is the complete question.

The population of a certain species of bird in a region after t years can be modeled by the function P(t) = 1620/ 1+1.15e-0.42t , where t ≥ 0. When will the population reach 1,200?

According to question we are to calculate the time t that the population P(t) will reach 1200.To do this we will substitute P(t) = 1,200 into the equation and calculate for the time 't'.

Given;

$P(t) = \frac{1620}{1+1.15e^{-0.42t} } \\\\at \ P(t)= 1200;\\\\1200 = \frac{1620}{1+1.15e^{-0.42t} }\\\\cross\ multiplying\\\\1+1.15e^{-0.42t} = \frac{1620}{1200} \\\\1+1.15e^{-0.42t} = 1.35\\\\1.15e^{-0.42t} = 1.35-1\\\\e^{-0.42t} = \frac{0.35}{1.15}\\ \\e^{-0.42t} = 0.3043\\\\Taking \ ln\ of\ both\ sides\\\\lne^{-0.42t} = ln0.3043\\\\-0.42t = -1.1897\\\\t = \frac{-1.1897}{-0.42} \\\\t = 2.8 years\\\\$