This is an incomplete answer sorry
Solve for y:
5 t = 9 y + 22
5 t = 9 y + 22 is equivalent to 9 y + 22 = 5 t:
9 y + 22 = 5 t
Subtract 22 from both sides:
9 y = 5 t - 22
Divide both sides by 9:
Answer: y = (5 t)/9 - 22/9
Answer:
The 99% confidence interval for p in this case is (0.3317, 0.5883).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
Randomly selects 100 students from the school and asks the President to name each one. The President is able to correctly name 46 of the students.
This means that:

99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence interval for p in this case is (0.3317, 0.5883).
I'm pretty sure its 5, because theres 15 on the one side and 10 on the other and the <em><u>?</u></em><em><u> </u></em> side would be 5 then.