First year:
.3 x 2593 = 777.9
$2593 - $777.90 = $1815.10
Second year:
.3 x 1815.10 = 544.53
$1815.10 - $544.53 = $1270.57
Third year:
.3 x 1270.57 = <span>381.171
$1270.57 - $381.171 = $</span>889.39900
$889.39900 rounded to the nearest hundredth is $889.40
Answer:
True
Step-by-step explanation:
For example:
HCF of 2 and 3 is 1
1/2 divide by reciprocal( flip the second fraction then multiple)
Answer:
The formatting on this is a little weird but if I'm reading it correctly:
1) 3.38
2) 7.29
3) 0.05
4) 0.42
Answer:
The required probability is 0.55404.
Step-by-step explanation:
Consider the provided information.
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.
Average error for 7 pages booklet and 5 pages booklet series is:
λ = 0.2×7 + 0.3×5 = 2.9
According to Poisson distribution: 
Where
is average number of events.
The probability of more than 2 typographical errors in the two booklets in total is:

Substitute the respective values in the above formula.



Hence, the required probability is 0.55404.