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Sidana [21]
3 years ago
7

What is 768, 473 in expanded form

Mathematics
1 answer:
Gekata [30.6K]3 years ago
7 0
700,000+60,000+8,000+400+70+3
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First year:
.3 x 2593 = 777.9

$2593 - $777.90 = $1815.10

Second year:
.3 x 1815.10 = 544.53

$1815.10 - $544.53 = $1270.57

Third year:
.3 x 1270.57 = <span>381.171

$1270.57 - $381.171 = $</span>889.39900

$889.39900 rounded to the nearest hundredth is $889.40
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True

Step-by-step explanation:

For example:

HCF of 2 and 3 is 1

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Add, subtract, multiply, or divide. Round answers to money problems to the nearest cent. Show how you solved these four problems
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7 0
3 years ago
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
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