Answer:
2 or 12
Step-by-step explanation:
The answer that we will use this equation 1/t1 +1/t2=1/ttotal
where t1 is the time of smaller pipe while t2 is the of the larger pipe
Given t total =4 while t2 is equal to t2=t1-6
So know you can solve the problem by changing it into (2t1-6)/(t1*(t1-6))=1/4
8( t1-3)=(t1^2-6t1)
t1^2-14t1+24=0
t1=2 or 12
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
x = 5y
xy = 320
Substitute the first equation into the second equation
(5y)(y) = 320
5y^2 = 320
y^2 = 64
y = 8 (y must be positive)
The integers are (x, y) = (40, 8).
Summary of problem.
annual production = 60000 units
work hours per worker = 200*12=2400 hours
productivity = 0.15 unit / person-hour
Need to calculate the number of workers/persons employed.
Each unit requires 1 unit / 0.15 unit/person-hour
= 1/0.15 person-hours / unit
60000 unit requires 60000 units * 1/0.15 person-hours/unit
= 400000 person-hours
400000 person-hours requires 400000 person-hours /2400 hours = 166.7 persons
=>
The plant has 167 labourers (assuming perfect attendance).
In the first octant, the given plane forms a triangle with vertices corresponding to the plane's intercepts along each axis.
Now that we know the vertices of the surface
, we can parameterize it by
where
and
. The surface element is
With respect to our parameterization, we have
, so the surface integral is
