Step-by-step explanation:
We want to find two things-- the speed of the boat in still water and the speed of the current. Each of these things will be represented by a different variable:
B = speed of the boat in still water
C = speed of the current
Since we have two variables, we will need to find a system of two equations to solve.
How do we find the two equations we need?
Rate problems are based on the relationship Distance = (Rate)(Time).
Fill in the chart with your data (chart attached)
The resulting speed of the boat (traveling upstream) is B-C miles per hour. On the other hand, if the boat is traveling downstream, the current will be pushing the boat faster, and the boat's speed will increase by C miles per hour. The resulting speed of the boat (traveling downstream) is B+C miles per hour. Put this info in the second column in the chart. Now plug it into a formula! <u>Distance=(Rate)(Time) </u>Now solve using the systems of equations!
Answer:
Step-by-step explanation:
Lines l and m are the parallel lines and 't' is a transversal line,
Therefore, ∠1 ≅ ∠5 [Corresponding angle postulate]
∠5 ≅ ∠7 [Vertical angles theorem]
∠1 ≅ ∠7 [Transitive property]
Therefore, ∠1 ≅ ∠7 [Alternate exterior angles theorem]
I think it would look like this 1/100^-10 hope dis helped
Best Answer: <span>4/3x-6y, 1/5x-10y
= 4/3(x-2y) , 1/5(x-2y)
LCD = 3 × 5(x – 2y) = 15(x – 2y</span>