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Paul [167]
3 years ago
10

Write the missing number that makes each equation true. Show your work. __ - 4 = 16 - 5

Mathematics
2 answers:
spin [16.1K]3 years ago
7 0

Answer:

15

Step-by-step explanation:

15-4=11

16-5=11

therefore both solutions = 11 and is  true

aivan3 [116]3 years ago
6 0

it is 15 cuz 15-4=11 and ,16-5=11

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A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s heigh
Nataly_w [17]

Answer D). 9 ft is correct

Height of the ball at a horizontal distance of 10 feet is 9 ft

Step-by-step explanation:

A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s height (y).

Y(x) = -0.02x^{2} +0.8x+3

Question asked is " What will be height (Y) of the ball when X=10 ft "

Simply putting value of X in given equation

we get,

Y(x) = -0.02x^{2} +0.8x+3

Y(x) = -0.02(10)^{2} +0.8(10)+3

Y(x) = -0.02(100)} +8+3

Y(x) = -2 +8+3

Y(x) = 9

<em>Therefore,</em> Height of the ball at a horizontal distance of 10 feet is 9 ft

Answer D.  9 ft is correct

6 0
3 years ago
Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y
kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

substitute in the formula

d=\sqrt{(5-2)^{2}+(2-0)^{2}}

d=\sqrt{(3)^{2}+(2)^{2}}

dAB=\sqrt{13}\ units

step 2

Find the distance BC

substitute in the formula

d=\sqrt{(7-5)^{2}+(-1-2)^{2}}

d=\sqrt{(2)^{2}+(-3)^{2}}

dBC=\sqrt{13}\ units

step 3

Find the distance AC

substitute in the formula

d=\sqrt{(7-2)^{2}+(-1-0)^{2}}

d=\sqrt{(5)^{2}+(-1)^{2}}

dAC=\sqrt{26}\ units

step 4

Compare the length sides

dAB=\sqrt{13}\ units

dBC=\sqrt{13}\ units

dAC=\sqrt{26}\ units

dAB=dBC

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

(AC)^{2} =(AB)^{2}+(BC)^{2}

substitute

(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}

26=13+13

26=26 -----> is true

therefore

Is an isosceles right triangle

8 0
3 years ago
Fh
scZoUnD [109]

Answer:

ok so just get the v12{{9-))0} and =14

Step-by-step explanation:

4 0
2 years ago
What number is a factor of 12,but not a multiple of 3
choli [55]
There are 3 numbers as such.
First lets list all the factors of 12
1,2,3,4,6,12
now lets see which are multiples of 3
3,6 and 12 are multiples of 3
therefore we are left with
1,2 and 4
6 0
3 years ago
Read 2 more answers
A number between 0 and 1, expressed as one number over another, is called a
lbvjy [14]

Answer:

its called a frcaction

Step-by-step explanation:

3 0
3 years ago
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