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k0ka [10]
3 years ago
7

Name three ways in which unicellular organisms can move. Describe one of them.

Chemistry
2 answers:
pogonyaev3 years ago
4 0

........

Explanation:

Viefleur [7K]3 years ago
3 0

Answer:

Unicellular organisms achieve locomotion using cilia and flagella. By creating currents in the surrounding environment, cilia and flagella can move the cell in one direction or another.

Explanation:

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Write the Noble Gas Notation for Silicone
ozzi

Answer:

[Ne] 3s2 3p2

Explanation:

Neon (Ne) is the noble gas right before silicon (Si).

Then right after neon is the 3s subshell. It has two electrons and is full.

After 3s comes the 3p subshell, and silicon only has two electrons in the 3p subshell (you can just count the electrons in each subshell on your periodic table).

8 0
3 years ago
The theoretical yield of NaBr from
Dvinal [7]

the percent yield of the reaction is 100%.

The percent yield is calculated as the experimental yield divided by the theoretical yield x 100%:

% yield = actual yield / theoretical yield * 100%

% yield of a reaction in this case Rate

In this case, the molar mass of NaBr is 102.9 g / mol, as you know:

444 actual yield = 7.08 mol x 102.9 g / mol = 728.532 g

theoretical yield = 7.08 mol x 102.9 g / mol = 728.532 g

, Replaced by the definition of percent yield:

percent yield = 728.532 grams / 728.532 grams * 100%

percent yield = 100%

Finally, the percent yield of the reaction is 100%.

<h3 />

FeBr3 is iron bromide. Also known as iron bromide. Iron bromide is an ionic compound in which iron is in a +3 oxidation state.

Learn more about % yield here:brainly.com/question/27979178

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5 0
2 years ago
Phosphorus crystallizes in several different forms, one of which is a simple cube with an edge length of 238 pm. What is the den
algol13

<u>Answer:</u> The density of phosphorus is 3.81g/cm^3

<u>Explanation:</u>

To calculate the density of phosphorus, we use the equation:

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density

Z = number of atom in unit cell = 1  (CCP)

M = atomic mass of phosphorus = 31 g/mol

N_{A} = Avogadro's number = 6.022\times 10^{23}

a = edge length of unit cell = 238pm=238\times 10^{-10}cm    (Conversion factor:  1cm=10^{10}pm  )

Putting values in above equation, we get:

\rho=\frac{1\times 31}{6.022\times 10^{23}\times (238\times 10^{-10})^3}\\\\\rho=3.81g/cm^3

Hence, the density of phosphorus is 3.81g/cm^3

6 0
3 years ago
How well can you apply Charles’s law to this sample of gas that experiences changes in pressure and volume? Assume that pressure
anzhelika [568]

Answer:

A: 384

B: 0.85

C: 1.1

D: 221

Explanation:

3 0
3 years ago
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What is the molarity of a solution of 3.0 mol of KCl in 4.0L of water?
Sergio039 [100]

Answer:

awnser choice F

Explanation:

bc ik

8 0
2 years ago
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