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vladimir1956 [14]
3 years ago
13

Which compound is insoluble in water? (1) KOH (3) Na3PO4 (2) NH4Cl (4) PbSO4

Chemistry
2 answers:
VLD [36.1K]3 years ago
8 0

Ans: 4) PbSO4

Different compounds are soluble in water to a different extent, some of them are completely insoluble in water. Solubility rules help in identifying the water soluble and insoluble compounds.  

Based on the rules:

1) Salts of group IA (Li, Na, K, Rb and Cs) are soluble in water

2) Salts containing NH4+ ions are water soluble

3) All phosphates (PO4³⁻) are insoluble except those containing group IA elements and (NH4)₃PO4

4) All sulfates, SO4²⁻ salts are generally soluble with the exception of Ca2+, Sr2+, Ba2+, Hg₂²⁺, Hg2+, Pb2+ and Ag+

Therefore, among the given examples:

1) KOH contains group 1A (K) therefore soluble

2) Na3PO4 contains group IA element (Na), therefore soluble

3) NH4Cl contains NH4+ ion, therefore soluble

4) Sulfate of lead (Pb) is insoluble

Veseljchak [2.6K]3 years ago
3 0
The answer is (4) PbSO₄.

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A solution contains only sucrose and water. If the mole fraction of sucrose is 0.0558, determine the molality of sucrose.
lora16 [44]

Answer:

The correct solution is "3.28 m".

Explanation:

According to the question,

Mol fraction of solvent,

= 0.0558

Molar mass of water,

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Mol of H₂O in 1000 g water,

= 55.55 mol

Now,

Let the mol of solute will be "x mol".

Total mol in solution will be "55.55 + x".

As we know,

⇒ The mol fraction of solvent = \frac{x}{55.55+x}

                                        0.0558=\frac{x}{55.55+x}

                                                x=0.0558[55.55+x]

                                                x=3.09969+0.0558x

                               x-0.0558x=3.09969

                                               x=\frac{3.09969}{0.9442}

                                                  =3.38 \ m

5 0
3 years ago
The process of recovering a salt from a solution by evaporating the solvent is known as
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Crystallization is the correct answer for recovering salt from a solution by evaporating the solvent
8 0
3 years ago
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If a sample of oxygen gas originally at from 171.4 K has its temperature increased to 288.4 K and
julia-pushkina [17]

Answer:

V₂ = 0.95 L

Explanation:

Given data:

Initial temperature of gas = 171.4 K

Final temperature of gas = 288.4 K

Final volume = 1.6 L

Initial volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

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T₁ = Initial temperature

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Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₁ = V₂T₁ /T₂

V₂ = 1.6 L × 171.4 K / 288.4 k

V₂ = 274.24 L.K / 288.4 K

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