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butalik [34]
1 year ago
12

You need to prepare 500 mL of a 0.250 M NaOH solution for a titration. What mass of NaOH is needed to

Chemistry
1 answer:
VikaD [51]1 year ago
5 0

The mass of NaOH needed to prepare the solution is 5 g

<h3>What is molarity? </h3>

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

<h3>How to determine the mole of sodium hydroxide, NaOH</h3>

We'll begin by calculating the moles of NaOH. This can be obtained as follow:

  • Volume = 500 mL = 500 / 1000 = 0.5 L
  • Molarity = 0.25 M
  • Mole of NaOH =?

Mole = Molarity x Volume

Mole of NaOH = 0.25 × 0.5

Mole of NaOH = 0.125 mole

<h3>How to determine the mass of sodium hydroxide, NaOH</h3>

The mass of NaOH needed can be obtained as follow:

  • Molar mass of NaOH = 40 g/mol
  • Mole of NaOH = 0.125 mole
  • Mass of NaOH =?

Mass = mole × molar mass

Mass of NaOH = 0.125 × 40

Mass of NaOH = 5 g

Thus, to prepare the solution, measure 5 g of NaOH and place it in a 500 mL volumetric flask and make it up to the mark with water.

Learn more about molarity:

brainly.com/question/15370276

#SPJ1

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1) A common experiment to determine the relative reactivity of metallic elements is to place a pure sample of one metal into an
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Answer: Zn(s)+CuSO_4(aq)\rightarrow ZnSO_4+Cu

Explanation:-

Single replacement reaction is a chemical reaction in which more reactive element displaces the less reactive element from its salt solution.

As zinc is more reactive than copper, it could easily displace copper from its aqueous solution and thus leads to formation of zinc (II) sulfate and pure copper.

The chemical reaction can be represented as :

Zn(s)+CuSO_4(aq)\rightarrow ZnSO_4+Cu

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3 years ago
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The backbone of nucleic acids consists of
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Answer:

c. a phosphodiester bond between the 3' and 5' hydroxyl groups of neighboring sugars

Explanation:

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The bond is formed by the linkage of 3' carbon atom of one of the sugar unit to the 5' carbon atom of the another succeeding sugar unit.

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Martin slowly pours an unknown liquid into a container that originally had some water in it. He is measuring the temperature in
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Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of sodium sulfa
notka56 [123]

Answer:

27%

Explanation:

Hello,

The following information is missing, but I found it: "1.92 g of sodium sulfate is produced from the reaction of 4.9 g of sulfuric acid and 7.8 g of sodium hydroxide" so the undergoing chemical reaction is:

2NaOH+H_2SO_4-->Na_2SO_4+2H_2O

Now, to compute the percent yield, we must first establish the limiting reagent to subsequently determine the theoretical yield of sodium sulfate because the real (1.92g) is already given, thus, we consider the following procedure:

n_{NaOH}=7.8gNaOH*\frac{1molNaOH}{40gNaOH}=0.2molNaOH\\n_{H_2SO_4}=4.9gH_2SO_4*\frac{1molH_2SO_4}{98gH_2SO_4}=0.050molH_2SO_4\\

- The moles of sodium hydroxide that completely react with 0.05 moles of sulfuric acid are:

0.2molNaOH*\frac{1molH_2SO_4}{2molNaOH}=0.098molH_2SO_4

As this number is higher than the previously computed 0.05 moles of available sulfuric acid, one states that the sulfuric acid is the limiting reagent. Now, the theoretical grams of sodium sulfate are found via:

0.05molH_2SO_4*\frac{1molNa_2SO_4}{1mol H_2SO_4} *\frac{142.04gNa_2SO_4}{1molNa_2SO_4} =7.1gNa_2SO_4

Finally, the percent yield turns out into:

Y=\frac{1.92g}{7.1g} *100

Y=27.0%

Best regards.

6 0
2 years ago
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