You need to prepare 500 mL of a 0.250 M NaOH solution for a titration. What mass of NaOH is needed to

Chemistry

1 answer:

VikaD [51]2 years ago

5 0

The mass of NaOH needed to prepare the solution is 5 g

<h3>What is molarity? </h3>

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

<h3>How to determine the mole of sodium hydroxide, NaOH</h3>

We'll begin by calculating the moles of NaOH. This can be obtained as follow:

Volume = 500 mL = 500 / 1000 = 0.5 L
Molarity = 0.25 M
Mole of NaOH =?

Mole = Molarity x Volume

Mole of NaOH = 0.25 × 0.5

Mole of NaOH = 0.125 mole

<h3>How to determine the mass of sodium hydroxide, NaOH</h3>

The mass of NaOH needed can be obtained as follow:

Molar mass of NaOH = 40 g/mol
Mole of NaOH = 0.125 mole
Mass of NaOH =?

Mass = mole × molar mass

Mass of NaOH = 0.125 × 40

Mass of NaOH = 5 g

Thus, to prepare the solution, measure 5 g of NaOH and place it in a 500 mL volumetric flask and make it up to the mark with water.

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