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Luda [366]
3 years ago
14

Using Newton's Method, what is the formula for determining the nth term in a sequence of approximations to a solution of a polyn

omial equation
Mathematics
1 answer:
lorasvet [3.4K]3 years ago
7 0

Step-by-step explanation:

in newton rapson method

x_{n+1}=x_{n}-\frac{f\left(x_{n}\right)}{f^{\prime}\left(x_{n}\right)}

Let n=n-1

x_{(n-1)+1}=x_{n-1}-\frac{f\left(x_{n-1}\right)}{f^{\prime}\left(x_{n-1}\right)}

x_{n}=x_{n-1}-\frac{f\left(x_{n-1}\right)}{f^{\prime}\left(x_{n-1}\right)}

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What is the value of 8n when n = 2
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8n is 8 x n. If n is 2, then 8n is 8 x 2 which is 16! Hope that helps!
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Consider a collection of envelopes consisting of 1 red envelope, 3 blue envelopes, 2 green envelopes, and 3 yellow envelopes if
nasty-shy [4]

Answer:

the probability that at least one envelope is a yellow envelope is 16/21

Step-by-step explanation:

The probability that at least one envelope is a yellow envelope is P(Y);

P(Y) = 1 - P(Y)'

P(Y)' is the probability that no envelope is a yellow envelope.

Given;

red envelope = 1

blue envelopes = 3

green envelopes = 2

yellow envelopes = 3

Total = 9

Number of non-yellow envelope = 9 -3 = 6

(6 envelope are not yellow)

P(Y)' = P1 × P2 × P3

Since there is no replacement;

P(Y)' = 6/9 × 5/8 × 4/7

P(Y)' = 5/21

From equation 1;

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the probability that at least one envelope is a yellow envelope is 16/21.

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4 years ago
Please help me with this it is very important to my grade
arsen [322]

Answer:

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\sf \longmapsto \: \frac{{x}^{3}  -  {y}^{3} }{4} \\ \sf \longmapsto \:  \frac{ {4}^{3}  -  {2}^{3} }{4}  \\ \sf \longmapsto \:  \frac{64 - 8}{4}  \\ \sf \longmapsto \:  \frac{56}{4} \:  \:  \:  \:  \:  \:  \:  \:   \\ \sf \longmapsto \: 14

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3 years ago
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