Diameter of the basketball rim = 18 inches
Circumference of the standard basketball = 30 inches
Area of circle = π r²
Basketball rim = 3.14 * (18/2)² = 3.14 * 9² = 3.14 * 81 = 254.34 in²
Circumference of a circle = 2 π r
30 = 2 * 3.14 * r
r = 30 / (2*3.14) = 30 / 6.28 = 4.78 inches
Standard basketball = 3.14 * (4.78)² = 3.14 * 22.85 = 71.75 in²
254.34 - 71.75 = 182.59 in²
Answer:
7
Step-by-step explanation:
9514 1404 393
Answer:
7 in
Step-by-step explanation:
For width w in inches, the length is given as 2w+1. The area is the product of length and width, so we have ...
A = LW
105 = (2w +1)w
2w^2 +w -105 = 0
To factor this, we're looking for factors of -210 that have a difference of 1.
-210 = -1(210) = -2(105) = -3(70) = -5(42) = -6(35) = -7(30) = -10(21) = -14(15)
So, the factorization is ...
(2w +15)(w -7) = 0
Solutions are values of w that make the factors zero:
w = -15/2, +7 . . . . . negative dimensions are irrelevant
The width of the rectangle is 7 inches.
Answer:
X = 2
Step-by-step explanation:
11 x 2 = 22
22 + 6 = 28
Answer:
I think the answer is 432 cubic inches( in^3). Answer is the first option.
