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Neko [114]
3 years ago
15

en una balansa de platillos esta equilibrada, en uno de los platillos hay una piedra, una pesa de un noveno kilogramos y la otra

de dos tercios kilogramos. en el otro platillo hay una pesa de un medio kilogramo y la otra de un tercio kilogramo. ¿cuanto pesa la piedra? ¿alguien me lo explica?
Mathematics
2 answers:
Tatiana [17]3 years ago
7 0

La piedra pesa un octavo de kilogram

byeeeeeeeeeeeeeee

Komok [63]3 years ago
3 0

Se escribe una equacion y se resolve.

Vamos a usar x para representar el peso de la piedra.

En en platillo que tiene la piedra, el peso total es: x + 1/9 + 2/3

En el otro platillo: 1/2 + 1/3

La balanza esta equilibrada por eso los pesos en los platillos son iguales.

x + 1/9 + 2/3 = 1/2 + 1/3

x + 2/18 + 12/18 = 9/18 + 6/18

x + 14/18 = 15/18

x = 1/18

Respuesta: La piedra pesa un octavo de kilogramo.

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