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Pachacha [2.7K]
3 years ago
13

Luis rides his bicycle 34 mile in 5 minutes, or 112 hour, along the bike trail. Assuming he rides at a constant rate, what is hi

s speed, in miles per hour?
Mathematics
1 answer:
artcher [175]3 years ago
3 0

Answer:

408\frac{miles}{hour}

Step-by-step explanation:

we know that

To find the speed divide the total distance by the time

so

\frac{34}{(1/12)}=34*12=408\frac{miles}{hour}

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alukav5142 [94]
If AC bisects < BAD, it means it cuts it into 2 equal parts

so < BAC = < CAD

3x + 12 = 5x
12 = 5x - 3x
12 = 2x
12/2 = x
6 = x

< BAC = 3x + 12.......3(6) + 12 = 30 degrees <===
6 0
3 years ago
Solve: |2 + 4x| 11
erastovalidia [21]

Correct option is A) [-13/4, 9/4] .

<u>Step-by-step explanation:</u>

Here we have following equation as  |2 + 4x| = 11 or , |2 + 4x| = 11 . We need to solve for the value of x .Let's find out:

We know that Modulus Function is both positive & negative for particular values of x , i.e.

|2 + 4x| is positive :

⇒ |2+4x|=11

⇒  2+4x=11

⇒  4x=9

⇒  x = \frac{9}{4}

|2 + 4x| is negative :

⇒ |2+4x|=11

⇒  -2-4x=11

⇒  -4x=13

⇒  x = \frac{-13}{4}

Therefore , Correct option is A) [-13/4, 9/4] .

5 0
3 years ago
WILL GIVE A BRAINLEST!!!!!!
Andrej [43]
We have that
<span>(c-4)/(c-2)=(c-2)/(c+2) - 1/(2-c)
 </span>- 1/(2-c)=-1/-(c-2)=1/(c-2)

(c-4)/(c-2)=(c-2)/(c+2)+ 1/(c-2)------- > (c-4)/(c-2)-1/(c-2)=(c-2)/(c+2) 
(c-4-1)/(c-2)=(c-2)/(c+2)---------------- > (c-5)/(c-2)=(c-2)/(c+2)

(c-5)/(c-2)=(c-2)/(c+2)------------- > remember (before simplifying) for the solution that c can not be 2 or -2
(c-5)*(c+2)=(c-2)*(c-2)------------------ > c²+2c-5c-10=c²-4c+4
-3c-10=-4c+4----------------------------- > -3c+4c=4+10----------- > c=14

the solution is c=14
 
the domain of the function is (-∞,-2) U (-2,2) U (2,∞) or 
<span>all real numbers except c=-2 and c=2</span>


5 0
3 years ago
Read 2 more answers
If a:b=5:6and b:c=3:8 find a:b:c?
mr_godi [17]

Answer:

(a x b ) : (b x b ) : (b x c)

5x3 : 6x3 : 6 x 8

Step-by-step explanation:

15:18:48

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Is there answers provided
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