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2 years ago

7

Solve for x x = 5 x = 18 x= 30° x = 36

1 answer:

Norma-Jean [14]2 years ago

8 0

Answer:

x=36

Step-by-step explanation:

5x=180

x=180/5=36

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In the square ABCD, AE = 3x + 5 and BD = 10x + 2. What is the length of line AC?

zubka84 [21]

BD = 2 AE
10 x + 2 = 2 * ( 3 x + 5 )
10 x + 2 = 6 x + 10
10 x - 6 x = 10 - 2
4 x = 8
x = 8 : 4
x = 2
And the line AC is equal to BD.
AC = 10 * 2 + 2 = 20 + 2 = 22
Answer:
3. 22

6 0

3 years ago

Write a real world problem that can be solved using the equation, 5x = 3x + 20

Natali5045456 [20]

-3x from both sides so it looks like 2x=20 and divide by 2 and x=10

8 0

2 years ago

10Hello, can you help me with this? How much is 5 raised to 5?

vesna_86 [32]

Answer:

A 5 by 5 Power in Trust is a clause that lets the beneficiary make withdrawals from the trust on a yearly basis. The beneficiary can cash out $5,000 or 5% of the trust's so-called fair market ...

Step-by-step explanation:

5^5

=5*5*5*5*5

=5^5

=3125

6 0

2 years ago

Eric's average income for the four months of the year 1450 point to $5 what must be his average income for the remaining eight m

Zielflug [23.3K]

Answer:

$2668.63

Step-by-step explanation:

If the average of 4 months is $5

Meaning the total sum for 4 months

4×5 =$20

If the average for the year was $1780.75

It means the total sum for a year is;

$1780.75×12 =$21369

This means the money received for the remaining 8 months is;

$21369-$20=$21349

Hence the average income for the remaining 8months is ;

The total amount for 8 months / 8;

$21349/8= $2668.625

$2668.63

8 0

2 years ago

Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t

NISA [10]

Answer:

Class second have higher score and have greater spread.

Step-by-step explanation:

For first box plot

$\text{Minimum value }= 53$

$Q_1=62$

$Median=80$

$Q_3=86$

$\text{Maximum value }= 89$

$Range=Maximum-Minimum=89-53=36$

$IQR=Q_3-Q-1=86-62=24$

For second box plot

$\text{Minimum value }= 56$

$Q_1=62$

$Median=74$

$Q_3=89$

$\text{Maximum value }= 96$

$Range=Maximum-Minimum=96-56=40$

$IQR=Q_3-Q-1=89-62=27$

First class has greater minimum value, it means first class has lower grades.

First quartile of both classes are same, it means equal number students in both classes have less than 62 marks.

First class has greater median.

second class has greater third quartile.

Second class has greater Maximum value. It means second class have higher score than first class.

Second class has greater range. It means the data of second class has greater spread.

Second class has greater inter quartile range. It means the data of second class has greater spread.

Therefore, the class second have higher score and have greater spread.

5 0

3 years ago