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Vikki [24]
3 years ago
12

Gentry Industries has the following information about maintenance costs in the past six months.

Mathematics
1 answer:
Vladimir [108]3 years ago
3 0

Answer:

Total cost= $5,425

Step-by-step explanation:

Giving the following information:

Month Machine _Hours Amount

January 200 $2,800

February 350 3,000

March 450 4,000

April 500 5,000

May 600 5,200

June 580 5,800

<u>First, we need to calculate the fixed and variable costs. To do it, we will use the high-low method:</u>

Variable cost per unit= (Highest activity cost - Lowest activity cost)/ (Highest activity units - Lowest activity units)

Variable cost per unit= (5,800 - 2,800) / (600 - 200)

Variable cost per unit= $7.5 per hour

Fixed costs= Highest activity cost - (Variable cost per unit * HAU)

Fixed costs= 5,800 - (7.5*600)

Fixed costs= $1,300

Fixed costs= LAC - (Variable cost per unit* LAU)

Fixed costs= 2,800 - (7.5*200)

Fixed costs= $1,300

<u>Now, we can determine the total cost for 550 hour</u>s:

Total cost= 1,300 + 7.5*550

Total cost= $5,425

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trapecia [35]

Given that quadrilateral QRST is a square.

Each angle of a square is of 90 degrees.

Angle <RQT is also an angle of 90 degrees.

We also given angle RQT = 3x - 6.

So, we can setup an equation as 3x-6 =90.

Now, we need to solve the equation for x.

6 is being subtracted from left side.

We always apply reverse operation. Reverse operation of subtraction is addition.

So, adding 6 on both sides of the equation, we get

3x-6+6 =90+6.

3x = 96.

3 is being multipied with x, in order to remove that 3, we need to apply reverse operation of multiplication.

So, dividing both sides by 3.

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3 years ago
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Answer:

a + c = 95........eq1

15a + 7c = 1,025....eq2

Step-by-step explanation:

Given:

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Number of adult tickets sold = a

Number of child tickets sold = c

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Number of adult tickets sold + Number of child tickets sold = Total number of ticket sold

a + c = 95........eq1

and

15a + 7c = 1,025....eq2

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See this solution/explanation (answer is '7 meters'):

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x=<u>7 [m]</u> - how far from the start of the lift hill...

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