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3 years ago

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How do you calculate compound interest? Please help me understand this

1 answer:

photoshop1234 [79]3 years ago

8 0

Answer:

Compound interest is calculated by multiplying the initial principal amount by one plus the annual interest rate raised to the number of compound periods minus one

Step-by-step explanation:

i just did it

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Many of you will live to the year 2100, which is not a leap year. Not all years which are divisible by 4 are leap years. A cente

Slav-nsk [51]

Answer:

For example, the years 1600, 2000, and 2400 are century leap years since those numbers are divisible by 400, while 1700, 1800, 1900, 2100, 2200, and 2300 are common years despite being divisible by 4.

Step-by-step explanation:

3 0

2 years ago

What are the domain restrictions of the expression g2−7g+10g3−6g2+8g ? Select each correct answer.

Sauron [17]

Answer with Step-by-step explanation:

We are given that an expression

$f(g)=\frac{g^2-7g+10}{g^3-6g^2+8g}$

We have to find domain restriction of the given function.

$f(g)=\frac{(g-5)(g-2)}{g(g-4)(g-2)}$

Domain restriction means : It is that value of x when substitute in function then function will not defined.

It means it is that values which makes denominator zero.

From given function we can see that

When substitute g=0 then it makes denominator zero.

Hence, the function is not defined at g=0

Substitute g=4

Then, it makes denominator zero.

Hence, function is not defined at g=4

Substitute g=2

Then,it makes denominator zero.

Hence, function is not defined at g=2

Therefore, the function is defined for all values of g except g=0, g=2 and g=4

5 0

3 years ago

Select the correct answer.

stira [4]

B, because the lines connect at (1,-4) and (4,-1)

3 0

2 years ago

PLZ HEEELLLLPPPPP!!!!!!

Alexeev081 [22]

Answer:

p=-7

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

PLEASE HELP 30 POINTS!!!!!!!!!!!!!!!!!!!!!!!

Anettt [7]

Since you know the value of "x", you can plug in the value for "x" in the equation.

[When an exponent is negative, you move it to the other side of the fraction to make the exponent positive.]

For example:

$x^{-2}$ or $\frac{x^{-2}}{1} =\frac{1}{x^2}$

$\frac{1}{y^{-3}} =\frac{y^3}{1}$ or y³

x = -2

f(x) = 9x + 7

f(-2) = 9(-2) + 7 = -18 + 7 = -11

$g(x)=5^x$

$g(-2)=5^{-2}=\frac{1}{5^2}=\frac{1}{25}$ (idk if you should have it as a decimal or a fraction)

x = -1

f(x) = 9x + 7

f(-1) = 9(-1) + 7 = -9 + 7 = -2

$g(x)=5^x$

$g(-1)=5^{-1}=\frac{1}{5}$

x = 0

f(x) = 9x + 7

f(0) = 9(0) + 7 = 7

$g(x)=5^x$

$g(0)=5^0=1$

x = 1

f(x) = 9x + 7

f(1) = 9(1) + 7 = 9 + 7 = 16

$g(x)=5^x$

$g(1)=5^1=5$

x = 2

f(x) = 9x + 7

f(2) = 9(2) + 7 = 18 + 7 = 25

$g(x)=5^x$

$g(2)=5^2=25$

You need to determine the solution of f(x) = g(x)

Since you know f(x) = 9x + 7 and $g(x)=5^x$ , you can plug in (9x + 7) for f(x), and ( $5^x$ ) into g(x)

f(x) = g(x)

$9x+7=5^x$ You can plug in each value of x into the equation

Your answer is x = 2 because when you plug in 2 for x in the equation, you get 25 = 25

5 0

3 years ago