H = 3b+2
A = (h*b)/2 28 = (3b+2)b/2 56 = 3b²+2b 0 = 3b² + 2b - 56
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Substitute.
2x+(2x -15) = -3
4x -15 = -3
Add 15 to both sides
4x = 12
Divide by 4
X=3
2(3) + y = -3
6+y=-3
-6 from both sides
Y=-9
(3,-9)
Answer:
n+4=32
Step-by-step explanation:
The initial number n gets additional 4 students making the new total number of students to be 32. Therefore, this situation can be represented as
n+4=32
To get the actual number of students before the additio, we make n the subject of formula hence
n=32-4
n=28
Therefore, the initial number was 28 and the equation is n+4=32
Since no choices were provided, the equation that can be modified is n+4=32
X/3 +4 = 5+x/6
6(x/3 +4 = 5+x/6)
2x+ 24 = 30 +x
x= 6
Answer:
B
Step-by-step explanation:
B is in Quadrant III.
B is the answer.
