All categories

2 years ago

What is the surface area?

Mathematics

1 answer:

finlep [7]2 years ago

8 0

Answer:

c. 166

Step-by-step explanation:

area = l x w

surface area = area

You might be interested in

Erin invested 15000 some at 5 percent and some at 8 percent annual interest if she recieves an annual return of 930 dollars how

eduard

.08x+.05(15000-x)=930
.08x+750-.05=930
.08x-.05x=930-750
.03x=180
X=180/.03=6,000 at 8%
(15000-6000)=9000 at 5%

8 0

3 years ago

The ratio of two numbers is 7 to 5. The sum of the numbers is 24. What are the numbers?

Kipish [7]

Answer:

14 and 10

Step-by-step explanation:

The ratio of the 2 numbers = 7x : 5x

The sum of the 2 numbers is 24, hence

7x + 5x = 24

12x = 24 ( divide both sides by 12 )

x = 2

7x = 7 × 2 = 14

5x = 5 × 2 = 10

Thus the numbers are 14 and 10

5 0

3 years ago

You pick a marble from a bag containing three black, four striped, and three white. What is the probability you will choose eith

bezimeni [28]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 80 ft deep. The bucket is f

zaharov [31]

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time $t$

At $t=0, the weight of the bucket is 6+36=42 \mathrm{lb}$

After $t$ seconds, the weight of the bucket is $42-0.15 t \mathrm{lb}$

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after $t$ seconds is $x=1.5 t$

Since the well is 80 ft deep, the time to pull out the bucket is $\frac{80}{2}=40 \mathrm{~s}$

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

$W=\int_{t=0}^{t=36} F d x$

Use $x=1.5 t$ and $F=42-0.15 t$

$W=\int_{0}^{36}(42-0.15 t)(1.5 d t)$

$=\int_{0}^{36} 63-0.225 t d t$

$=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}$

$=\left[63 t-0.2 t^{2}\right]_{0}^{36}$

$W=3200 \mathrm{ft} \cdot \mathrm{lb}$

4 0

3 years ago

the base and height of the triangle at the right are multiplied by 4.Describe the change in the area.Justify your answer.

Dima020 [189]

I need more information about the triangle before I am able to answer your question.

8 0

3 years ago