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grin007 [14]
3 years ago
15

What is b in terms of a and c?

Mathematics
1 answer:
aev [14]3 years ago
6 0

Answer:

b=\sqrt{c^2-a^2}

Step-by-step explanation:

The given relation is

c=\sqrt{a^2+b^2}

To make b the subject, we square both sides of the equation to get;

c^2=(\sqrt{a^2+b^2})^2

c^2=a^2+b^2

Isolate b on one side of the equation;

c^2-a^2=b^2

Or

b^2=c^2-a^2

We take the positive square root of both sides to get;

b=\sqrt{c^2-a^2}

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igomit [66]
The standard form is

(x-xo)² + (y-yo)² = r²

Where xo,yo is the center of the circumference
and r is the radius.

We find the distance between the points to determine the <span>diameter

d=sqrt ((9-2)</span>² + (4-4)²<span>) = sqrt (49) = 7

The radius of the circumference is d/2 = 7/2 = 3.5

And we can see that those points are at the same coordinate y = 4 

The center is given then by , x = (9+2)/2 = 5.5
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The equation results

(x-5.5)</span>² + (y-4)² = (3.5)²<span>

</span>
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3 years ago
Question within image.
julia-pushkina [17]

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6 0
3 years ago
Does anybody know the answer to all of these?
Mama L [17]

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6 0
3 years ago
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Write the equation of the line parallel to Y equals 2/3X +1 through the point (0,-4)  use slope intercept form
Andrew [12]

Writing the slope-intercept form of a linear equation, we have:

y=mx+b

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Since parallel lines have the same slope, we can see that the slope of the line y = 2/3x + 1 is equal m = 2/3, so for our equation we also have m = 2/3.

Now, using the point (0, -4), we have:

\begin{gathered} y=\frac{2}{3}x+b \\ (0,-4)\colon \\ -4=\frac{2}{3}\cdot0+b \\ b+0=-4 \\ b=-4 \end{gathered}

So our equation is:

y=\frac{2}{3}x-4

y = 2/3x - 4

7 0
1 year ago
point A is at (-5,-4) and point M is at (0,-3.5).Point M is the midpoint of point A and point Bwhat are the coordinates of point
velikii [3]

Answer:

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