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tiny-mole [99]
3 years ago
12

Why do I keep struggling in geometry. I'm in 10th grade I shouldn't be struggling but anyway my teacher let me retake a quiz/ te

st and I made the exact same score. So I have no clue what to do.
Mathematics
2 answers:
Nastasia [14]3 years ago
7 0

Answer:

yeah, Geometry is not that easy. I struggled a bit in Geometry, too. You have to study a lot. Im an Algebra person im good with equations. Geometry has to many rules and theorems and other stuff you need to remember. Try studying. If you Need help you can comment for help and i will try to help you with what i can.  Im in 10th grade but i have Algebra 2. Also, i have a Geometry book with other stuff, etc... I'll be glad to help you if i can.

Step-by-step explanation:

skad [1K]3 years ago
6 0

Step-by-step explanation:

I don't know what you need to do. Have you studied the quiz or more specific have you studied the questions that you have problems with? Also make sure you have enough sleep and have healthy food. You don't have to do read what I say(type) but it could help you.

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When there is a wedge between private costs and social costs, which of the following must be present?
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Verify the property a x (b+c) =(a x b)+(a x c) by taking: a = -7, b = (2/5), c = (-3/7)
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5 0
3 years ago
The length of a rectangle is 8 more than the width. The area is 105 square centimeters. Find the length and width of the rectang
sashaice [31]

Answer:

Width =  7 cm

Length = 15 cm

Step-by-step explanation:

Let width = w

Length = w + 8

Area of rectangle = 105 sq. cm

length * breadth = 105

(w + 8)*w = 105

Use distributive property

w² + 8w = 105

w² + 8w - 105 = 0

Sum = 8

Product = -105

Factors = 15 , -7   {15 +(-7) = 8 & 15*(-7) = -105}

w² - 7m + 15m - 105 = 0

w(w - 7) + 15(m - 7) = 0

(w - 7)(w + 15) = 0

Ignore w + 15= 0 as measurements will not be in negative value

w - 7 = 0

w = 7

Width = 7 cm

Length = 7 + 8 = 15 cm

8 0
2 years ago
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6 0
2 years ago
The length and breadth of a room are 3 meter and 4 meter. What is the length of the largest metallic rod that can be placed in i
anyanavicka [17]

Length = l = 3 m ,

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= √ 25

= 5

I hope this helps you.

8 0
3 years ago
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