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Answer:
Latency of an object O is shown below.
Explanation:
W segment and stalled state transmits nothing and waits for acknowledgement. The latency is 2 R TT + the time required for server that are using to transmit the object + the amount of time when server is in stalled state. Let K be the number of window that is K= O/WS .The serveries stalled state where K-1 is period of ime with period lasting RTT-(W-1)S/R
latency = 2RTT +O/R +(K-1)[S/R +RTT - WS/R]
After combining the two case
latency = 2 RTT + O/R + (K-1)[S/R +RTT - WS/R]
where [x] means maximum of (x.0). This is the complete ananlysis of the static windows.
server time for transmit the object is (K-1)[S/R +RTT - WS/R]
Answer:
It is the user tier of the 3-tier architecture that consists of computers, phones, and other mobile devices that have browsers that request and process web pages.
Explanation:
Almost if not all applications that use e-commerce for operations use the 3-tier architecture. 3-tier architecture is simply the arrangement of server tier which consists of all computers that run a web server and a database tier that consists of computers that run a DBMS to store and retrieve data. We also have the user data that consists of computers, phones, and other mobile devices that have browsers that request and process web pages.
When you make a request, for instance to Google in your local browser, the browser sends a request to the internet. This initial interaction between the user and the internet is what is known as the user tier of the 3 tier architecture. Basically, it is the phase where end users access content online through graphical interface browsers and make requests to the web servers and DBMS.
Learn more about 3-tier architecture
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Answer:
a) Yes
b) Yes
c) Yes
d) No
e) Yes
f) No
Explanation:
a) All single-bit errors are caught by Cyclic Redundancy Check (CRC) and it produces 100 % of error detection.
b) All double-bit errors for any reasonably long message are caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit. It also produces 100 % of error detection.
c) 5 isolated bit errors are not caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit since CRC may not be able to catch all even numbers of isolated bit errors so it is not even.
It produces nearly 100 % of error detection.
d) All even numbers of isolated bit errors may not be caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit. It also produces 100 % of error detection.
e) All burst errors with burst lengths less than or equal to 32 are caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit. It also produces 100 % of error detection.
f) A burst error with burst length greater than 32 may not be caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit.
Cyclic Redundancy Check (CRC) does not detect the length of error burst which is greater than or equal to r bits.
Turn off your computer, wait 10 minutes, turn it back on. Open your browser, and go to the website. If it is still not working, I would assume that this is not a problem with your computer, but the network was not loaded properly, and should be fixed with some patience. In the mean time, you may have the day off.
