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3 years ago

In the right -angled tringles began the ABC in the ED :8cm ,and DC :10cm then the length of the air

Mathematics

1 answer:

fgiga [73]3 years ago

7 0

ED:8cm,DC:10 so the air is HD:18

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Which expression is equivalent to 3(5x - 4)<br>A. 8x - 4<br>B. 8x - 1<br>C. 15x - 4<br>D. 15x - 12

zalisa [80]

Answer:c

15x - 4

Step-by-step explanation:

15x - 4

3 0

3 years ago

Read 2 more answers

PQR has vertices at P(-10, 8), Q(0, -6),

nirvana33 [79]

Answer:

please apply the formula of distance

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2 years ago

In a cohort of 35 graduating students, there are three different prizes to be awarded. If no student can receive more than one p

sweet [91]

We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.

To solve this problem we will use permutations.

$_{r}^{n}\textrm{P}={_{3}^{35}\textrm{P}}$

We know that formula for permutations is given as

$_{r}^{n}\textrm{P}=\frac{n!}{(n-r)!}$

On substituting the given values in the formula we get,

${_{3}^{35}\textrm{P}}=\frac{35!}{(35-3)!}=\frac{35!}{32!}$

$=\frac{35\cdot 34\cdot 33\cdot 32!}{32!}\\
\\
=35\cdot 34\cdot 33=39270$

Therefore, there are 39270 ways in which prizes can be awarded.

6 0

3 years ago

Copy the problems onto your paper, mark the given and prove the statements asked. Given: marked Prove: ΔABC ≅ ΔDBC, ΔEHF ≅ ΔGHF

hjlf

The proof is given below. Please go through it.

Step-by-step explanation:

To solve Δ ABC ≅ Δ DBC

From Δ ABC and Δ DBC

AB = BD (given)

AC = CD (given)

BC is common side

By SSS condition Δ ABC ≅ Δ DBC ( proved)

To solve Δ EHF ≅ Δ GHF

Δ EHF and Δ GHF

EH = HG ( given)

∠ EFH = ∠ GFH ( each angle is 90°)

HF is common side

By RHS condition

Δ EHF ≅ Δ GHF

7 0

3 years ago

PLEASE HELP!! Dee bought 6 dolls and 2 toy trains for $55. At the same prices, Joy bought 4 dolls and 7 toy trains for $65. What

GuDViN [60]

Answer:

The cost of 1 doll = $ 7.5

and The Cost of 1 toy train = $ 5

Step-by-step explanation:

Let the price of 1 doll = $ x

The price of 1 toy train = $ y

Now, according to the question:

6 x + 2 y = $ 55

and 4 x + 7 y = $ 65

Solving the given system of equation,

From (1), we get

$x= \frac{55 - 2y}{6}$

$4 ({\frac{55 - 2y}{6}} ) + 7y = 65$

or, solving for y , we get

110y - 4y + 21 y = 195

or, 17 y = 85

⇒ y= 85/17 = 5

This implies : 6 x + 2 (5) =55

or, 6x = 55 - 10 = 45

or, x = 45/ 6 = 15/2

Hence, the cost of 1 doll = x = $ 7.5

and the Cost of 1 toy train = y = $ 5

5 0

3 years ago