It’s prime because none of the other answers work.
Where is it?
step by step:
The end behavior of the function y = x² is given as follows:
f(x) -> ∞ as x -> - ∞; f(x) -> ∞ as x -> - ∞.
<h3>How to identify the end behavior of a function?</h3>
The end behavior of a function is given by the limit of f(x) when x goes to both negative and positive infinity.
In this problem, the function is:
y = x².
When x goes to negative infinity, the limit is:
lim x -> - ∞ f(x) = (-∞)² = ∞.
Meaning that the function is increasing at the left corner of it's graph.
When x goes to positive infinity, the limit is:
lim x -> ∞ f(x) = (∞)² = ∞.
Meaning that the function is also increasing at the right corner of it's graph.
Thus the last option is the correct option regarding the end behavior of the function.
<h3>Missing information</h3>
We suppose that the function is y = x².
More can be learned about the end behavior of a function at brainly.com/question/24248193
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Answer:
Step-by-step explanation:
x² - 24x + 5 = 0
x² - 24x = -5
Now divide the co efficient of x by 2 and square the quotient and add to both sides
24/2 = 12
12² = 144. Now add 144 to both sides of the equation.
x² - 24x + 144 = 5 + 144
x² - 24x + 144 = 149
x² - 2*12*x + 12² = 149
(x - 12)² = 149
Both sides take square root
x - 12 = ±√149
x = 12 ± √149
