Answer: $53.95
Step-by-step explanation:
Given:
pounds
pounds
n= 50
Two tailed critical z-value for 90% confidence level = 1.645
Let x be the total amount of food that a cafeteria should have on hand to be 90 percent confident that it will not run out of food .
z-score =
![=\dfrac{x-0.75}{0.2}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7Bx-0.75%7D%7B0.2%7D)
Then, ![\dfrac{x-0.75}{0.2}=1.645](https://tex.z-dn.net/?f=%5Cdfrac%7Bx-0.75%7D%7B0.2%7D%3D1.645)
![x-0.75=1.645\times0.2\\\\\Riightarrow\ x-0.75=0.329\\\\\Rightarrow\ x= 0.329+0.75\\\\\Rightarrow\ x= 1.079](https://tex.z-dn.net/?f=x-0.75%3D1.645%5Ctimes0.2%5C%5C%5C%5C%5CRiightarrow%5C%20x-0.75%3D0.329%5C%5C%5C%5C%5CRightarrow%5C%20x%3D%200.329%2B0.75%5C%5C%5C%5C%5CRightarrow%5C%20x%3D%201.079)
Foe 50 students, total amount of food = 1.079 x 50 = $53.95
hence, the cafeteria should have food of amount $53.95 so that it is be 90 percent confident that it will not run out of food.
Answer:
11√3-7√6
im good at these, just hit me up if you need more help ;)
The first thing you would do is divide 34 by 3, which is how many feet are in a yard, After you get your quotient, you will have a remainder, which will be your feet! Let me know if you have any questions!
<h3>
Answer: 3^5</h3>
Explanation:
The rule used is ![\left(\frac{a}{b}\right)^{-c} = \left(\frac{b}{a}\right)^{c}](https://tex.z-dn.net/?f=%5Cleft%28%5Cfrac%7Ba%7D%7Bb%7D%5Cright%29%5E%7B-c%7D%20%20%3D%20%5Cleft%28%5Cfrac%7Bb%7D%7Ba%7D%5Cright%29%5E%7Bc%7D)
That rule says to go from a negative exponent to a positive exponent, we apply the reciprocal of the fraction.
So,
![\left(\frac{1}{3}\right)^{-5} = \left(\frac{3}{1}\right)^{5} = 3^5](https://tex.z-dn.net/?f=%5Cleft%28%5Cfrac%7B1%7D%7B3%7D%5Cright%29%5E%7B-5%7D%20%3D%20%5Cleft%28%5Cfrac%7B3%7D%7B1%7D%5Cright%29%5E%7B5%7D%20%3D%203%5E5)
Answer:
.
Step-by-step explanation:
Start by separating this decimal number into its integer part and its fraction part:
![4.151515\cdots = 4 + 0.151515\cdots](https://tex.z-dn.net/?f=4.151515%5Ccdots%20%3D%204%20%2B%200.151515%5Ccdots)
The most challenging task here is to express
as a proper fraction. Once that fraction is found, expressing the original number
will be as simple as rewriting a mixed number as an improper fraction.
Let
.
would then represent the original number.
Note that the repeating digits appear in groups of two. Therefore, if the digits in
are shifted to the left by two places, the repeating part will continue to match:
.
Note, that this "shifting" is as simple as multiplying the initial number by
(same as
raised to the power of the number of digits that needs to be shifted.)
Subtract the original number from the shifted number to eliminate the fraction part completely:
.
In other words:
.
.
Therefore, the original number would be:
.