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Misha Larkins [42]
3 years ago
7

Subtract . Your answer should be a polynomial in standard form. (- 5b ^ 2 - 8b) - (- 9b ^ 3 - 5b ^ 2 - 8b) =

Mathematics
2 answers:
Zarrin [17]3 years ago
8 0

Answer:

9b³

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Distributive Property

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

(-5b² - 8b) - (-9b³ - 5b² - 8b)

<u>Step 2: Simplify</u>

  1. [Distributive Property] Distribute negative:                                                  -5b² - 8b + 9b³ + 5b² + 8b
  2. [Addition] Combine like terms (b²):                                                               9b³ - 8b + 8b
  3. [Addition] Combine like terms (b):                                                                 9b³
sveta [45]3 years ago
5 0

Answer:9b3

Step-by-step explanation:

Distribute the Negative Sign:

=−5b2−8b+−1(−9b3−5b2−8b)

=−5b2+−8b+−1(−9b3)+−1(−5b2)+−1(−8b)

=−5b2+−8b+9b3+5b2+8b

Combine Like Terms:

=−5b2+−8b+9b3+5b2+8b

=(9b3)+(−5b2+5b2)+(−8b+8b)

=9b3

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1. A company has a cash portfolio measured in millions. The drift is 0.1 per month, variance is 0.16per month. The initial cash
Romashka-Z-Leto [24]

Answer:

Step-by-step explanation:

From the information given:

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After 6 months;

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The company's cash position is supposed to be allocated monthly, with the following expenses.

Mean                            2.6

Standard deviation     0.9798

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Mean = value of Initial cash  + \alphaT

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The standard deviation is:

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Hence, after 6 months;

The company's cash position is supposed to be allocated monthly, with the following expenses.

Mean                            3.2

Sandard deviation      1.3856

Variance                      1.92

b)  

in 6-month distribution, the probability of the negative value of the cash position is as follows.

Now, for us to find the negative cash distribution;

We need to estimate the z -scores value.

The z-score inform us greatly on the concept of how far a particular data point is from the mean.

For a normal distribution;

z = \dfrac{x-\mu}{\sigma}

Here;

the value of x = zero as a result that if it exceeds zero. the cash position will be negative.

∴

z = \dfrac{x-\mu}{\sigma}

z = \dfrac{0 - 2.6}{0.9798}

z = -2.6536

Using the standard distribution tables, it is now possible to calculate that the likelihood N(-2.65) equals 0.004 or 0.4 percent.

As a result, there's a 0.4 percent chance of getting a negative cash balance after six months.

For 12 months distribution:

The Probability of negative cash position is calculated as follows:

z = \dfrac{x-\mu}{\sigma} \\ \\ z = \dfrac{0-3.2}{1.3856} \\ \\ z = -2.3094

Using the standard distribution tables,

N(-2.31) equals 0.0104 or 1.04 percent.

As a result, there's a 1.04 percent chance of getting a negative cash balance after 1 year  

c) To determine the time period over which the likelihood of achieving a negative cash condition is highest, it's necessary to examine the z-score more closely. Essentially, the z-score measures the difference between a given value(x) and the mean of all potential values (\mu), expressed in terms of the total set's standard deviation (\sigma)

This suggests that the higher the z-score, the greater the difference occurring between x and \mu, and thus the likelihood of receiving x is minimal. As a result, the best chance of finding a certain value is when the z-score is the lowest.

To do so, calculate the derivative of the z-score in relation to the time interval. The point where the derivative is equivalent to zero is where the z-scores are at their lowest.

The first step is to go over the z-score formula in more detail, as seen below.;

z = \dfrac{x-\mu}{\sigma} \\ \\ z = \dfrac{0-(initial \ value + \alpha T)}{b \sqrt{T}} \\ \\ z = \dfrac{-initial \ value }{b\sqrt{T}}-\dfrac{a \sqrt{T}}{b} \\ \\

Now, compute the derivative of this equation with respect to T as follows:

\dfrac{dz}{dT}= \dfrac{initial \ value \times T^{-\dfrac{3}{2}}}{2b} - \dfrac{aT^{-\dfrac{1}{2}}}{2b}

Now, figure out the value of T at which this derivative is equal to zero by substituting all values as follows:

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As a result, the time period in which achieving a negative cash condition is = 20 months.

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Answer:

B

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