speed of current is 1.5 mi/hr
Answer:
let the rate in still water be x and rate of the current be y.
speed down the river is:
speed=distance/time
speed=14/2=7 mi/h
speed up the river is:
speed=(14)/(3.5)=4 mi/hr
thus total speed downstream and upstream will be:
x+y=7...i
x-y=4.......ii
adding the above equations i and ii we get:
2x=11
x=5.5 mi/hr
thus
y=5-5.5=1.5 mi/r
thus the speed in still waters is 5.5 mi/hr
speed of current is 1.5 mi/hr
Answer:
I think its D
Step-by-step explanation:
The dot starts on -2 and decreases so the answer would = -2 or be less than -2 :)
Answer:
Step-by-step explanation:
![Area=\frac{1}{2}*b*h\\\\=\frac{1}{2}*7x*8x\\\\=7x*4x\\\\=28x^{2}](https://tex.z-dn.net/?f=Area%3D%5Cfrac%7B1%7D%7B2%7D%2Ab%2Ah%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B2%7D%2A7x%2A8x%5C%5C%5C%5C%3D7x%2A4x%5C%5C%5C%5C%3D28x%5E%7B2%7D)
G(x)=x²
The graph has moved to the right 4 units, therefore the new graph will be:
H(x)=(x-4)²
It has also move 4 units up, therefore the new graph will be:
F(x)=(x-4)²+4
Answer:
F(x)=(x-4)²+4
Answer:
![(7,\frac{13}{3})](https://tex.z-dn.net/?f=%287%2C%5Cfrac%7B13%7D%7B3%7D%29)
Step-by-step explanation:
we have
<em>The equation of the first line</em>
------> equation A
<em>The equation of the second line</em>
------> equation B
Solve the system of equations by elimination
Multiply equation A by -4 both sides
--------> equation C
Adds equation B and equation C
![y=\frac{4}{3}x-5\\-4y=-\frac{4}{3}x-8\\--------\\y-4y=-5-8\\-3y=-13\\y=\frac{13}{3}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B4%7D%7B3%7Dx-5%5C%5C-4y%3D-%5Cfrac%7B4%7D%7B3%7Dx-8%5C%5C--------%5C%5Cy-4y%3D-5-8%5C%5C-3y%3D-13%5C%5Cy%3D%5Cfrac%7B13%7D%7B3%7D)
<em>Find the value of x</em>
substitute the value of y
![\frac{13}{3}=\frac{1}{3}x+2](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B3%7D%3D%5Cfrac%7B1%7D%7B3%7Dx%2B2)
![\frac{1}{3}x=\frac{13}{3}-2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7Dx%3D%5Cfrac%7B13%7D%7B3%7D-2)
Multiply by 3 both sides
![x=13-6](https://tex.z-dn.net/?f=x%3D13-6)
![x=7](https://tex.z-dn.net/?f=x%3D7)
therefore
The solution to the system of equations is the point ![(7,\frac{13}{3})](https://tex.z-dn.net/?f=%287%2C%5Cfrac%7B13%7D%7B3%7D%29)