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iren [92.7K]
3 years ago
10

What is the value of n in the equation shown below? 2²×2n=(2

Mathematics
1 answer:
pychu [463]3 years ago
4 0

Answer:

<h3>n = 1/4</h3>

Step-by-step explanation:

2^2 \times 2n= (2)\\\\\mathrm{Simplify\:}2^2\times\:2n:\quad 8n\\\\\mathrm{Simplify\:}\left(2\right):\quad 2\\\\8n=2\\\\\mathrm{Divide\:both\:sides\:by\:}8\\\\\frac{8n}{8}=\frac{2}{8}\\\\Simplify\\\\n=\frac{1}{4}

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denpristay [2]

Answer:

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Step-by-step explanation:

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3 years ago
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Just need to know what x is haha
marishachu [46]

Answer: x=14

Step-by-step explanation:

The angles in a triangle are equal to 180 so

6x + 3 + 5x + x + 9 = 180

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3 years ago
Write the explicit formula for the geometric sequence 2, 8, 32, 128
Alja [10]
The first term, a, is 2.  The common ratio, r, is 4.  Thus,

a_(n+1) = 2(4)^(n).

Check:  What's the first term?  Let n=1.  Then we get 2(4)^1, or 8.  Is that correct?  No.

Try this instead:

a_(n) = a_0*4^(n-1).  Is this correct?    Seeking the first term (n=1), does this formula produce 2?      2*4^0 = 2*1 = 2.  YES.

The desired explicit formula is   a_(n) = a_0*4^(n-1), where n begins at 1.


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3 years ago
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5 0
3 years ago
A psychological experiment was conducted to investigate the length of time (time delay) between the administration of a stimulus
aleksklad [387]

Answer:

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

The significance level for this test is 0.05.

Step-by-step explanation:

In this case, we want to prove if there is significant evidence that the mean differs from 1.6 seconds. That is the same as having evidence to reject the the hypothesis H_0:\mu= 1.6 (the null hypothesis always have the equal sign).

We have to test the null hypothesis

H_0:\mu= 1.6

The significance level for this test is 0.05

Calculation of the t-statistic:

t=\frac{M-\mu}{s/\sqrt{n}} =\frac{2.2-1.6}{0.57/\sqrt{36}} =\frac{0.6}{0.063}= 9.47

If we look up in a t-table for t=9.47 and df=(36-1)=35, we get this value appears with a probability of zero. A large number like that is very unlikely to happen.

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

6 0
2 years ago
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