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Brums [2.3K]
3 years ago
15

Colin pays £721.45 a year on his car insurance.

Mathematics
2 answers:
laila [671]3 years ago
6 0

Answer:

Id

I forget

Step-by-step explanation:

Lesechka [4]3 years ago
4 0
The answer is 655.08, 9.2% of £721.45=66.3734, 721.45-66.3734=655.0766, when you round it to 2DP the final answer would be 655.08
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Does any one know how to do determining the GFC
nataly862011 [7]

Answer:

Yes, GCF stands for (greatest common factor)

so to find it do this:

   List the prime factors of each number.

   Circle every common prime factor — that is, every prime factor that's a factor of every number in the set.

   Multiply all the circled numbers. The result is the GCF.

Step-by-step explanation:

4 0
3 years ago
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Leokris [45]

Answer:

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Step-by-step explanation:

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3 years ago
Is a line is represented by a straight narrow segment with arrow signs at the end? ...?
Luda [366]
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3 years ago
Determine the center and radius of the following circle equation:<br> x2 + y2 – 10x + 8y + 40 = 0
antiseptic1488 [7]

Answer:

The center of this circle is (5, -4) and the radius is 1.

Step-by-step explanation:

First regroup these terms according to x and y :

x^2 - 10x + y^2 + 8y = -40

Next, complete the square for x^2 - 10x:  x^2 - 10x + 5^2 - 5^2.

and the same for y^2 + 8y:  y^2 + 8y + 16 - 16

Substituting these results into x^2 - 10x + y^2 + 8y = -40, we get:

x^2 - 10x + 5^2 - 5^2 y^2 + 8y + 16 - 16 = -40.

Next, rewrite x^2 - 10x + 25 and y^2 + 8y + 16 as squares of binomials:

Then x^2 - 10x + 5^2 - 5^2 y^2 + 8y + 16 - 16 = -40 becomes:

(x - 5)^2 + (y + 4)^2 - 25 - 16 = -40, or:

(x - 5)^2 + (y + 4)^2 = 1

This equation has the form (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius.  Matching like terms, we get h = 5, k = -4 and r = 1.

The center of this circle is (5, -4) and the radius is 1.

6 0
3 years ago
Read 2 more answers
13. The relationship 1/sin(θ) is equivalent to which of the following trigonometric functions?
d1i1m1o1n [39]
The rigt answer i checked os csc
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3 years ago
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